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Sergeu [11.5K]
2 years ago
10

I need help with those 2.

Physics
1 answer:
Nimfa-mama [501]2 years ago
5 0

Hi there!

Question 1:

We know that Impulse = Δp = mΔv, so:

I = 0.045(70) = 3.15 Ns

I = F · t, so:

3.15/0.1 = F

F = 31.5 N

Question 2.

We can find the impulse using:

I = Ft

I = 300 · 0.04 = 12 Ns

Find the change in velocity using:

I = mΔv

12/0.13 = Δv = 92.31 m/s

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Answer:Jack will run faster when he feels like it!

Explanation:

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A train travels 8.81 m/s in a -51.0° direction.
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The displacement of the train after 2.23 seconds is 25.4 m.

<h3>Resultant velocity of the train</h3>

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

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R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

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<h3>Displacement of the train</h3>

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Learn more about displacement here: brainly.com/question/2109763

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A team of scientists wants to conduct a study on an endangered animal inthe wild. Which rule should the study follow in order to
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A runner starts from rest and in 3 s reaches a speed of 8 m/s. If we assume that the speed changed at a constant rate (constant
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Answer:

The average speed of the runner is 4 m/s.

Explanation:

Hi there!

The average speed (a.s) is calculated by dividing the traveled distance (d) over the time needed to travel that distance (t):

a.s = d / t

So, let´s find the distance traveled in those 3 s. For that, we can use the equation of position of an object moving in a straight line with constant acceleration:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

If we place the origin of the frame of reference at the point where the runner starts, then, x0 = 0. Since the runner starts from rest, v0 = 0. So, the equation gets reduced to this:

x = 1/2 · a · t²

We have the time (3 s), so let´s find the acceleration. For that, we can use the equation of velocity of an object moving in a straight line with constant acceleration:

v = v0 + a · t

Where "v" is the velocity at a time "t". Since v0 = 0, then:

v = a · t

At t = 3 s, v = 8 m/s

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So let´s find the position of the runner at t = 3 s (In this case, the position of the runner will be equal to the traveled distance):

x = 1/2 · a · t²

x = 1/2 · 8/3 m/s² · (3 s)²

x = 12 m

Now, we can calcualte the average speed:

a.s = d/t

a.s = 12 m / 3 s

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The average speed of the runner is 4 m/s.

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