Answer:
C) 3
I played a while with desmos. when I diverge from c=3 it seems impossible to fit the graph even remotely to the point, the lowest point won't fit if it isn't 3
note that it's still just the best approximation out of the 4 given options
Answer:
Step-by-step explanation:
The segment addition theorem tells you ...
CD +DE = CE
x^2 +12x = 32 -2x
Subtract the right side to put this in standard form.
x^2 +14x -32 = 0
(x +16)(x -2) = 0
x = -16 or 2
In order for DE to have a positive length, we must have x > 0. So ...
CD = x^2 = 2^2 = 4
DE = 12x = 12(2) = 24
CE = 32 -2x = 32 -2(2) = 28
Answer:
735,471
Step-by-step explanation:
by combination
Answer:
LFGA is a rectangle
B) yes they are
Since lf=ag
LFE=AGT
AT=LE
SO THEY ARE CONGRUENT HAVING 2 EQUAL SIDES AND ONE RIGHT ANGLE
C) ef =gt
(U have to prove them before)
D) LF is equal to AG
Since in a rectangle the h times base
