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Sloan [31]
3 years ago
6

Answer choices: 0 1 -1 -2 ( chose this and got it wrong so it's not this)

Mathematics
2 answers:
Hitman42 [59]3 years ago
8 0
Average rate of change =(y2 - y1)/(x2 - x1)

For x1=-2, y1 = -1.
For x2=0, y2=-1.

Average rate of change =(-1 + 1)/(0 +1) =0

Answer is 0. 
If you connect these 2 points, you will see that line is horizontal, slope is 0, so average rate of change is 0.
Dmitry [639]3 years ago
5 0
Use the formula for average rate of change over an interval of two points:

\frac{y_2 - y_1}{x_2 - x_1}

We have two points: (-2, -1) and (0, -1). Plug the values into the formula:

\frac{-1 - (-1)}{0 - (-2)} = \frac{0}{2} = 0

The average rate of change over the interval [-2,0] is 0.
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3 years ago
MZ1 = _º<br> 140<br> 160<br> 80<br><br><br> what is M
Ilia_Sergeevich [38]

Answer:

80

Step-by-step explanation:

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3 years ago
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wolverine [178]

Answer:x = -8

Step-by-step explanation:

7 0
2 years ago
A typical running track is an oval with 74-m-diameter half circles at each end. a runner going once around the track covers a di
denpristay [2]

Answer:

Her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

Step-by-step explanation:

Total distance covered in one round , D= 400 m

Time taken to cover one round , T = 1 min 40 s = 100 sec

Speed of runner , V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}

Now centripetal acceleration is given by

a_c=\frac{V^{2}}{R}

where V= 4.0\frac{m}{s}

Radius, R= \frac{Diameter}{2}=\frac{74}{2}m=37\, m

\therefore a_c=\frac{4^{2}}{37}\, \frac{m}{s^{2}}=0.432\, \frac{m}{s^{2}}

Thus her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

4 0
3 years ago
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PilotLPTM [1.2K]

The measure of angle AEB is 19 degrees

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