<em>5x + 2y = 25;</em>
<em>5x + 2y = 25;5x - y = 10;</em>
5x + 2y = 25;
5x = 10 + y;
(10 + y) + 2y = 25;
5x = 10 + y;
10 + 3y = 25;
5x = 10 + y;
3y = 15;
5x = 10 + y;
y = 5;
5x = 10 + y;
y = 5;
5x = 10 + 5;
y = 5;
5x = 15;
y = 5;
x = 3.
Answer: (3; 5).
Answer: 110°
<u>Step-by-step explanation:</u>
∠A ≅ ∠B
since ∠A = 35° (given), then ∠B = 35°
Use the Triangle Sum Theorem to find ∠C:
∠A + ∠B + ∠Q = 180°
35° + 35° + ∠Q = 180°
70° + ∠Q = 180°
∠Q = 110°
The central angle (∠AQB) ≅ arc AB
since ∠AQB = 110° (solved above), then arc AB = 110°
X(4*1) because I’m just doing what I’m told.
Answer:
answer is -1 according to calculation
Answer:
BC ≈ 4.0
Step-by-step explanation:
∠ DCA = 180° - 70° = 110° ( adjacent angles )
∠ DAC = 180° - (30 + 110)° ← sum of angles in triangle
∠ DAC = 180° - 140° = 40°
Using the Sine rule in Δ ACD to find common side AC
= 
( cross- multiply )
AC × sin40° = 15 × sin30° ( divide both sides by sin40° )
AC = 
≈ 11.668
Using the cosine ratio in right triangle ABC
cos70° = 
= 
= 
( multiply both sides by 11.668 )
11.668 × cos70° = BC , then
BC ≈ 4.0 ( to the nearest tenth )
