Answer:
Population of dice mice after one year = 2000
Population of wood rats after one year = 1000
The population of deer mice is growing faster than the popular of wood rats
Step-by-step explanation:
The expression for population = dN/dt = rN
Upon integration N = rN²/2
Therefore for population N = 200 and r= 0.1
N after one year = (0.1 x 200²)/ 2 = 2000
Therefore for population N = 100 and r= 0.2
N after one year = (0.2 x 100²)/ 2 = 1000
Hence the population of deer mice is growing faster than the popular of wood rats
59 cans ... she counting up by 5s so multiply 5 x 10
Answer:
Step-by-step explanation:
Part A
xf = xo + vo* t + 1/2 a*t^2 Subtract xo
xf - xo = 0*t + 1/2 a*t^2 multiply by 2
2(xf - xo) = at^2 divide by t^2
2(xf - xo ) / t^2 = a
Part B
Givens
xo =0
vo = 0
a = 10 m/s^2
xf = 120 m
Solution
xf = xo + vo* t + 1/2 a*t^2 Substitute the givens
120 = 0 + 0 + 1/2 * 10 * t^2 Multiply by 2
120*2 = 10* t^2
240 = 10*t^2 Divide by 10
240/10 = t^2
24 = t^2 take the square root of both sides.
√24 = √t^2
t = √24
t = √(2 * 2 * 2 * 3)
t = 2√6
Answer:
−x²−4x+3−x+3
Subtract x from −4x.
−x²−5x+6
Step-by-step explanation:
