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zubka84 [21]
3 years ago
15

Identify the fraction as proper, improper, or mixed . (If the fraction is equivalent to 1, choose "one" in the blank.) 3/8

Mathematics
1 answer:
Katena32 [7]3 years ago
6 0
The fraction is proper fraction

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(Look at screenshot)
PilotLPTM [1.2K]

#a

H(0)

It refers to y value on graph when x is 0

So here it refers to y intercept

  • y intercept (0,5)

Hence

  • H(0)=5

#b

Observe the graph

y intercept is not 0 so it's not true

#3

Domain is set of x values in graph

  • [0,oo)

#4

Range is set of y values on graph

  • [5,50]
4 0
2 years ago
If $5000 is invested at 7.8% interest compounded monthly, how much would you have after 54 months?
Nuetrik [128]

5000 x (1+0.078/12)^54

5000 x (1.0065)^54

$7094.37

6 0
3 years ago
?????????!??!!?!?!?!?!?!?!?
vivado [14]

Answer:

Option 4:  y > 2x

                x + 2y < -8

Step-by-step explanation:

Taking first equation:

y > 2x

Putting x = 0

y > 0

Putting y = 0

0 > x

So the blue line in drawn according to first equation.

Taking second equation:

 x + 2y < -8

Putting x = 0

 2y < -8

y < - 4

putting y = 0

 x < -8

So the red line is drawn accordingly.

i hope it will help you!

7 0
3 years ago
State if the two triangles are congruent. if they are state how you know.
nlexa [21]
1) The triangles are congruent by SSS.

The two tick marks indicate two pairs of congruent sides; it is evident that the third side is congruent by the way the diagram is drawn - the bases of the triangles are together and appear to be the same length.

2) The triangles are congruent by SAS.

The two pairs of tick marks indicate congruent sides, and their included angles are congruent because they are vertical angles, and vertical angles are always congruent.
5 0
3 years ago
If the initial amount of iodine-131 is 537 grams , how much is left after 10 days?
viktelen [127]

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

4 0
3 years ago
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