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Anvisha [2.4K]
3 years ago
5

How many potassium hydroxide (KOH) formula units are present in 6.89 mol of KOH?

Chemistry
2 answers:
MatroZZZ [7]3 years ago
7 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of formula units or atoms or molecules into number of moles.

</span>6.89 mol KOH (<span>6.022 x 10^23 formula units / mole) = 4.1498 x 10^24 formula units

Therefore, the correct answer is option A.
</span>
Orlov [11]3 years ago
7 0
I believe there would be A. 4.1498x10^24 formula units in 6.89 moles of KOH.
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Answer:

The mass of 3.491 × 10¹⁹ molecules of Cl₂  of Cl₂ is 4.11 × 10⁻³ grams

Explanation:

The number of particles in one mole of a substance id=s given by the Avogadro's number which is approximately 6.023 × 10²³ particles

Therefore, we have;

One mole of Cl₂ gas, which is a compound, contains 6.023 × 10²³ individual molecules of Cl₂

3.491 × 10¹⁹ molecules of Cl₂ is equivalent to (3.491 × 10¹⁹)/(6.023 × 10²³) = 5.796 × 10⁻⁵ moles of Cl₂

The mass of one mole of Cl₂ = 70.906 g/mol

The mass of 5.796 × 10⁻⁵ moles of Cl₂ = 70.906 × 5.796 × 10^(-5) = 4.11 × 10⁻³ grams

Therefore;

The mass of 3.491 × 10¹⁹ molecules of Cl₂  of Cl₂ = 4.11 × 10⁻³ grams.

4 0
3 years ago
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Contact [7]

Answer:

Explanation:

Hello,

At first, they differ because a physical property is observed without changing the nature of the substance. On the other hand, a change in the nature of the substance must be carried out to observe a chemical property.

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