Many trials are not needed before a hypothesis can be accepted
1 answer:
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Question is incomplete, complete question is as follows :
Complete Question : .Sulfonation of benzene has the following mechanism:
(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3
[fast]
(2) SO3 + C6H6 → H(C6H5+)SO3−
[slow]
(3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4
[fast]
(4) C6H5SO3− + H3O+ → C6H5SO3H + H2O
[fast]
write the overall rate law for the initial rate of the reaction as a fraction.
Rate=k(________/_________)
Answer:
The overall rate law for the initial reaction is =
Explanation :
Frist of all, all the common terms are cancelled out and written the overall reaction.
As we know that the rate depednant step is the slowest step of the reaction, rate law is :
rate =
But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.
Rate law for synthesis of S03 is as follows :
rate =
Hence when we substitute equation 2 in equation one,
Rate comes out to be =
Answer:
volume of gas = 9.1436cm³
Explanation:
We will only temperature from °C to K since the conversion is done by the addition of 273 to the Celsius value.
Its not necessary to convert pressure and volume as their conversions are done by multiplication and upon division using the combined gas equation, the factors used in their conversions will cancel out.
V1 =10.1cm³ , P1 =746mmHg, T1=23°C =23+273=296k
V2 =? , P2 =760mmmHg , T2=0°C = 0+273 =273K
Using the combined gas equation to calculate for V2;
V2=9.1436cm³