Wind turbine B has blades twice as long as wind turbine A. If they are subjected to the same wind, what is the relationship betw
1 answer:
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Answer:
Ff= 8.9N:Force of friction acting on the block.
Explanation
Box kinetics: in x₁-y₁ :We apply the second law of Newton
∑Fx₁=ma : second law of Newton Formula (1)
Where:
∑Fx₁:algebraic sum of forces in the direction of x1, positive in the direction of movement of the block, which is down and negative in the direction opposite to the movement of the block
m: is the mass of the block
The x₁ axis coincides with the plane of sliding of the block, that is, the x₁ axis forms 45 degrees with the horizontal
The total weight (W) of the block is in the vertical direction and the tip of the vector down and its magnitude is calculated as follows:
W=m*g
Where:
m: is the mass of the block
g: is the acceleration due to gravity
Calculation of the weight in the direction x₁
Wx₁=Wcos45°= m*g*cos 45 Equation( 1)
Data
m=1.8kg
g=9.8 m/s²
a=2m/s
Wx₁=m*g*cos 45°= 1.8*9.8 *= 12.47 N
Friction force (Ff ) calculation
We apply formula (1)
∑Fx₁=m*a
Wx₁ - Ff= m*a
Ff=Wx₁ - m*a
We replace data
Ff= 12.47 - 1.8*2 =8.87
Ff= 8.9N