a pitcher contains 40 fluid ounces of iced tea. Shelby pours 3 cups of iced tea. how many pints of iced tea are left?

2 answers:

8 0

8 ounce=1 cup
so 3 cups=8 times 3 ounces=24 ounces
40-24=16 counces left

8 ounces=1 cup
16 ounces=2 times 8
16=2 cups
2 cups=1 pint
1 pint left

lord [1]3 years ago

4 0

Given;
40 fluid ounces of iced tea.

We know,
1 cup = 8 fluid ounce
1 pint = 2 cup

Now,
8 fluid ounce = 1 cup
1 fluid ounce = 1 / 8 cup
40 fluid ounce = (1 / 8) * 40 cup
So, 40 fluid ounce = 5 cup

Now,
We, used 3 cups of iced tea. So, we only have 2 cups of iced tea left.

We have,
2 cups = 1 pint

So, 1 pint of iced tea is left!

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The diagonals of this rhombus are 8 and 16 units long. Their intersection creates four right angles, two 4-unit-long segments, a

Roman55 [17]

Answer:

$64\ \text{sq. units}$

Step-by-step explanation:

Area of a rhombus is the product of the length of the diagonals divided by two.

Length of one diagonal is 8 units and the other diagonal is 16 units

Area is given by

$A=\dfrac{8\times 16}{2}\\\Rightarrow A=64\ \text{sq. units}$

The area of the rhombus is $64\ \text{sq. units}$

Another approach is the diagonals have created 4 triangles where the base and is height is either 4 units long or 8 units long so the area of the rhombus would be the area of the 4 triangles.

$A=4\times \dfrac{1}{2}\times 4\times 8\\\Rightarrow A=64\ \text{sq. units}$