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Kisachek [45]
3 years ago
13

Bridget has 32 pencils and 48 pens she wants to make identical bags of pencils and pens to give to her friend what is the highes

t number of friends that she can give a bag to and have nothing left over?
Mathematics
2 answers:
Vikki [24]3 years ago
8 0
You’re just looking for the greatest common factor here which would be 16 as 32/16=2 (a whole number) and 48/16=3 (a whole number)

Hope this helps :))
AleksandrR [38]3 years ago
8 0

See https://web2.0calc.com/questions/please-help_75042.

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Convert (1/3)^x=27 to logarithmic form, with work worked out!
Sophie [7]

{a}^{x}  = m \\  log_{a}(m)  = x

( \frac{1}{3} )^{x}  = 27 \\  log_{ \frac{1}{3} }(27)  = x

That's the logarithmic form. Do you need with solving the equation too?

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2 years ago
Please help me! Please please please help me!
photoshop1234 [79]
Graph C is the correct option.

If you drew a straight line (mostly) connecting the points, it would be linear. A relationship is linear if one variable, in this case, x, increases by approximately the same rate as the other variables, in this case y.

If you drew lines connecting points on the other graphs, they wouldn’t resemble a straight line, therefore, they aren’t linear.
5 0
3 years ago
Express the solution of, x^3 + 2x^2 < x + 2, using interval notation.
Rudiy27

x³ + 2x² - x - 2 < 0

x³ - x + 2x² - 2 < 0

x(x² - 1) - 2(x² - 1) < 0

(x - 2)(x² - 1) < 0

(x - 2)(x - 1)(x + 1) < 0

by chacking we get the solution

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6 0
2 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 139 millimeters,
FinnZ [79.3K]

Answer:

0.4010 = 40.10% probability that the sample mean would differ from the population mean by more than 0.8 millimeters

Step-by-step explanation:

To solve this question, we need to understan the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 139, \sigma = 6, n = 40, s = \frac{6}{\sqrt{40}} = 0.9487

Either the sample mean differs by 0.8 mm or less from the population mean, or it differs by more. The sum of these probabilities is decimal 1.

Probability it differs by less than 0.8mm

pvalue of Z when X = 139 + 0.8 = 139.8mm subtracted by the pvalue of Z when X = 139 - 0.8 = 138.2 mm

X = 139.8

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{139.8 - 139}{0.9487}

Z = 0.84

Z = 0.84 has a pvalue of 0.7995

X = 138.2

Z = \frac{X - \mu}{s}

Z = \frac{138.2 - 139}{0.9487}

Z = -0.84

Z = -0.84 has a pvalue of 0.2005

0.7995 - 0.2005 = 0.5990

What is the probability that the sample mean would differ from the population mean by more than 0.8 millimeters?

p + 0.5990 = 0.4010

0.4010 = 40.10% probability that the sample mean would differ from the population mean by more than 0.8 millimeters

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286 feet; use the numbers and find the area of each rectangle, then add them all together.
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