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vaieri [72.5K]
3 years ago
8

What ends in 1258I will say that you cool in comments ​

Mathematics
2 answers:
dimaraw [331]3 years ago
7 0

Answer:

NUMBERS end in 12581... YEP.

JulijaS [17]3 years ago
3 0

Answer:

End 12581 yes

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The slope of a line is 58, and the line passes through the point (−8,−4).
nadezda [96]

Answer:

y=58x+460

Step-by-step explanation:

y=mx+b

We are given m=58 so we have

y=58x+b

We are given (-8,-4) is a point on the line.

-4=58(-8)+b

-4=-464+b

460=b

So the line in slope intercept form is y=58x+460

5 0
3 years ago
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Which point on the graph represents they-intercept
kobusy [5.1K]

Answer: W is the correct answer just for clarification.

Step-by-step explanation:

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3 years ago
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5. State whether the number 91 is prime, composite, or neither.
Zolol [24]

Answer:

91 is a composite number

Step-by-step explanation:

A prime number is the positive number, which has factors 1 and itself.

Example : 1,3,5,7

Clearly 91 is not a prime number, as its factors are:

91 = 1,7,13,91

It has more than 2 factors (1 and itself), hence 91 is a composite number.

Composite number is the number which has factors other than 1 and itself.

7 0
4 years ago
URGENT PLEASE HELP!!!!.The binary operation (*)is defined on the set of integers p and q by p*q=pq+p+q. find 2*(3*4)​.I will mar
skad [1K]

Answer:

2 is odd or –3 is not negative.

Step-by-step explanation:

Which of the following statement is the negation of the statement, “2 is even and –3 is negative”?

(A)  2 is even and –3 is not negative.

(B) 2 is odd and –3 is not negative.

(C) 2 is even or  –3 is not negative.

(D) 2 is odd or –3 is not negative.

3 0
3 years ago
Two similar hexagons have corresponding heights of 3 m and 4 m. If the area of the smaller hexagon is 13 m2, what is the area of
Setler [38]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\cfrac{smaller}{larger}\qquad \cfrac{3}{4}=\cfrac{\sqrt{13}}{\sqrt{a}}\implies \cfrac{3}{4}=\sqrt{\cfrac{13}{a}}\implies \left( \cfrac{3}{4} \right)^2=\cfrac{13}{a}
\\\\\\
\cfrac{3^2}{4^2}=\cfrac{13}{a}\implies \cfrac{9}{16}=\cfrac{13}{a}\implies a=\cfrac{16\cdot 3}{9}
8 0
3 years ago
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