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prohojiy [21]
3 years ago
11

Convert fraction with numerator 9 and denominator 16 to a decimal. 0.4225 0.5225 0.5625 0.7455

Mathematics
2 answers:
OleMash [197]3 years ago
7 0
5625 is the answer. hope it helps!
liberstina [14]3 years ago
4 0

Answer:

.5625

Step-by-step explanation:

We know that

9/16

is the same as

9÷16

We have the equation:

9 ÷ 16 = 0.5625

Calculated to 4 decimal places.

   0. 5 6 2 5

1 6 9. 0 0 0 0

 − 0        

   9 0      

 − 8 0      

   1 0 0    

 −   9 6    

       4 0  

     − 3 2  

         8 0

       − 8 0

           0

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there are 18 bikes in the bike rack there are four more blue bikes than yellow bikes and two less yellow bikes and green bikes h
jeyben [28]
So
green bikes:20
yellow bikes:20. but don't really understand
blue bikes:22
8 0
3 years ago
Robin has a certain number of dimes in his pocket. If the dimes were pennies, he would have $1.08 less than he has now. How many
laiz [17]

Answer:

Robin will have 12 dimes in his pocket.

Step-by-step explanation:

Since;

D = One dime = $0.1

P = One penny = $0.01

Amount to have less = $1.08

From the above, when a dime is changed to a penny, the amount held by Robin will decrease by $0.09. That is,

Decease in holding = D - P = $0.1 - $0.01 = $0.09

Therefore, we have:

Number of dimes = Amount to have less / Decease in holding = $1.08 / $0.09 = 12 dimes

Therefore, Robin will have 12 dimes in his pocket.

4 0
2 years ago
An artist made purple paint by mixing 1/2 quart of red paint and 3/4 quart of blue paint. What is the ration of red paint to blu
Orlov [11]

Answer:

(1/2)/(3/4) = (1/2)(4/3) = 2/3

Step-by-step explanation:

4 0
3 years ago
Billy has 95 stickers. He shares 4 with<br> Harry. How many stickers will Billy have?
Leni [432]

Answer: 91

Step-by-step explanation:

95 - 4 (That he gave to Harry) = 91

Hope this helped!

7 0
3 years ago
Read 2 more answers
For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}

Split the summand into partial fractions:

\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

1=a(1+4)\implies a=\frac15

This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

and as n\to\infty, the second term vanishes and leaves us with

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

7 0
3 years ago
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