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Salsk061 [2.6K]
3 years ago
11

Are the following equations perpendicular y=-1/3x+4 and y=1/3x+12?

Mathematics
1 answer:
g100num [7]3 years ago
3 0
<h3>Answer: No, they are not perpendicular</h3>

Explanation:

Compare each equation to the form y = mx+b

m = slope

The first equation has slope -1/3 and the second equation has slope 1/3

The slopes do not multiply to -1, so the lines aren't perpendicular.

The slopes aren't equal, so the line aren't parallel either.

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arsen [322]
Use 5 as the lowest common factor and you gt 3/20
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Three forces act on a hook. Determine the magnitude of the resultant of the force.
Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y

\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y

\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y

The resultant force is the sum of these vectors,

\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y

and has magnitude

|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N

The closest answer is D.

5 0
3 years ago
10x−y = 10<br> −2x+ 5y = −2
Viefleur [7K]

Answer:

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Step-by-step explanation:

5 0
1 year ago
What is the simplify rational expression for 10b + 100
igor_vitrenko [27]

Answer:

10 (b+10)

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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Have an amazing day!

PLEASE MARK BRAINLIEST!

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3 years ago
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