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Salsk061 [2.6K]
4 years ago
11

Are the following equations perpendicular y=-1/3x+4 and y=1/3x+12?

Mathematics
1 answer:
g100num [7]4 years ago
3 0
<h3>Answer: No, they are not perpendicular</h3>

Explanation:

Compare each equation to the form y = mx+b

m = slope

The first equation has slope -1/3 and the second equation has slope 1/3

The slopes do not multiply to -1, so the lines aren't perpendicular.

The slopes aren't equal, so the line aren't parallel either.

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Pls answer as much as u can I’ll mark u pls :(
True [87]

Answer:

12. 10.5 cm

13. 16 m

14. 8 m

15. 50.24 m

16. 200.96 m2

17. (16+4 =20 ÷2 =10 ·10·π =314 ÷2 =157) + (16·4 =64) =221 in2

18. (1.1 · 1.2 =1.32) + (1.2 · 4 =4.8 ÷2 =2.4) =3.72 in2

19. 10·5=50

20. c.(1/2 d)^2·π

7 0
3 years ago
How to construct the circumcenter of a triangle?
Step2247 [10]
U just x it to the tingles
6 0
4 years ago
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A coffee pot holds 5 1/2 quartz of coffee. How much is his in cups?
never [62]
. So there are 4 cups in a quart. So multiply 2 3/4 quarts by 4 to get
(2 3/4) * 4 =
(11/4) * 4 =
11 cups
3 0
3 years ago
1.<br> Solve for x=<br> 35, 103
mariarad [96]

Given:

A figure of a circle with secants intersecting inside the circle.

To find:

The value of x.

Solution:

According to the intersection theorem of secants, if two secants intersect each other inside the circle, then the angle on the intersection is the average of the intercepted arcs.

Using the intersection theorem of secants, we get

x^\circ=\dfrac{1}{2}(35^\circ+103^\circ)

x^\circ=\dfrac{1}{2}(138^\circ)

x^\circ=69^\circ

x=69

Therefore, the value of x is 69.

6 0
3 years ago
Find the sum of 5 and 6, then raise it to the power of two, and finally subtract the quotient of 15 and 5. Write the expression
Anna [14]

Answer: (5+6)^2-(\frac{15}{5} ) and solved is 118

Step-by-step explanation:

Finding the sum of 5 and 6 indicates the addition

5+6

It then says raise it to the power of two so let's put it in parenthesis so it can be solved before raising it to the power of two

(5+6)^2

The quotient of 15 and 5 indicates division so we can put that in its own parenthesis too and then subtract it when solved.

(5+6)^2-(\frac{15}{5} )

If you need to solve start by solving the parenthesis

(5+6)^2-(\frac{15}{5} )\\&#10;(11)^2-(3)

then raise 11 to the power of 2

121-3

finally, subtract

118

7 0
3 years ago
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