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sveta [45]
3 years ago
14

In parallelogram PQSR, what is PQ?

Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

PQ is parallel to RS and both are vertical components of parallelogram

Step-by-step explanation:

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PLSS HELP ASAP IF YOU TURLY KNOW THIS
sladkih [1.3K]

Answer:

10,000 :)

Step-by-step explanation:

5,089 rounded =5,000

4,722 rounded= 5,000

=  10,000

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2 years ago
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Can you please help me fill this out thanks
RoseWind [281]
For perimeter you just add the sides up, so 15+12+9 which = 36
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3 years ago
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Which points define the solution set
Lemur [1.5K]

There is a line and a parabola in the graph.

So, we will get the solution set from the point of intersection of both line and parabola.

Notice that the parabola and the line intersecting at two points E(1, 5) and C(-0.5,2).

So, the solution set is E(1, 5) and C(-0.5,2).

8 0
3 years ago
The formula v equals the square root of the quantity 64 multiplied by h end of quantity gives the velocity v in feet per second
NemiM [27]
The equation is derived from the conservation of energy, specifically from potential energy stored at a given height in a gravitational field.

When potential energy is completely converted to kinetic energy you have:

(mv^2)/2=mgh  divide both sides by the mass m

v^2/2=gh  multiply both sides by 2

v^2=2gh take the square root of both sides

v=√(2gh)  and working with imperial units for acceleration due to gravity, g=-32ft/s^2

v=√(-64h)  but the change of h as it falls is negative h so

v=-√(64h) so if an object falls from a height of 88ft we have:

v=-√(64*84)

v=-√5376

v≈-73.32 ft/sec (to the nearest hundredth of a foot per second)

Note that this is the velocity, it is negative 73.32 ft/sec.

The question inadvertently asked for velocity and provided answers for SPEED.  Velocity is a vector and has both magnitude and direction, whereas speed just has magnitude.

So its final speed is 73.32 ft/sec

So if they actually wanted velocity none of their answers is correct :P
5 0
3 years ago
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Bacteria of species A and species B are kept in a single environment, where they are fed two nutrients. Each day the environment
DiKsa [7]

Answer:

We require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

Step-by-step explanation:

Let n₁ be the population of A required and n₂ be the population of B required.

Now we require 2 units of the first nutrient for species A and one unit of the first nutrient for species B. The total nutrients required by species A is 2n₁ and that by species B is 1n₂ = n₂. So, the total nutrients required by both species A and B is 2n₁ + n₂. Since this equals the quantity of the first nutrient which is 10,560, then  2n₁ + n₂ = 10,560 (1)

Now we require 5 units of the second nutrient for species A and 6 units of the second nutrient for species B. The total nutrients required by species A is 5n₁ and that by species B is 6n₂. So, the total nutrients required by both species A and B is 5n₁ + 6n₂. Since this equals the quantity of the first nutrient which is 31,510, then  5n₁ + 6n₂ = 31,510 (2).

So, we have two simultaneous equations which we would solve to find the populations of A and B which satisfy both equations.

2n₁ + n₂ = 10,560  (1)

5n₁ + 6n₂ = 31,510 (2)

From (1) n₂ = 10,560 - 2n₁ (3)

Substituting equation (3) into (2), we have

5n₁ + 6(10,560 - 2n₁) = 31,510

expanding the brackets, we have

5n₁ + 63,360 - 12n₁ = 31,510

collecting like terms, we have

5n₁ - 12n₁ = 31,510 - 63,360

simplifying, we have

- 7n₁ = -31,850

dividing both sides by -7, we have

n₁ = -31,850/-7

n₁ = 4,550

Substituting n₁ = 4,550 into (3), we have

n₂ = 10,560 - 2(4,550)

n₂ = 10,560 - 9,100

n₂ = 1,460

So, we require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

3 0
2 years ago
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