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miv72 [106K]
3 years ago
11

A triangle has a base length given by the equation b = 2x + 4 and a height given by the equation h

Mathematics
1 answer:
Anna11 [10]3 years ago
7 0
It’s 230 I hope this helps
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The mean of 100 observation is found to be 40. If at the time of compution two items were wrongly taken as 30 and 27 instead of
Colt1911 [192]

Answer:

40.18

Step-by-step explanation:

According to this question, the mean of 100 observation is found to be 40. This means that the number of values in the set of data is 100. However, at the time of computation two items were wrongly taken as 30 and 27 instead of 3 and 72.

The mean is derived by dividing the sum of values in the data (Σx) by the number of observations (n) i.e.

Mean = Σx/n

For the computation error:

Mean = 40

Let x represent the sun of other 98 values except 30 and 27

n = 100

40 = x + 30 + 27/100

40 = 57 + x/100

Cross multiply

4000 = 57 + x

x = 4000 - 57

x = 3943.

Sum of other 98 values = 3943.

Now, let's find the correct mean with correct values of 3 and 72;

Mean = Σx/n

Mean = 3943 + 3 + 72/100

Mean = 4018/100

Mean = 40.18

7 0
2 years ago
Does the set {t, t Int} form a fundamental set of solutions for t^2y" -- ty' +y = 0?
Ivanshal [37]

Answer:

yes

Step-by-step explanation:

We are given that a Cauchy Euler's equation

t^2y''-ty'+y=0 where t is not equal to zero

We are given that two solutions of given Cauchy Euler's equation are t,t ln t

We have to find  the solutions are independent or dependent.

To find  the solutions are independent or dependent we use wronskain

w(x)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}

If wrosnkian is not equal to zero then solutions are dependent and if wronskian is zero then the set of solution is independent.

Let y_1=t,y_2=t ln t

y'_1=1,y'_2=lnt+1

w(x)=\begin{vmatrix}t&t lnt\\1&lnt+1\end{vmatrix}

w(x)=t(lnt+1)-tlnt=tlnt+t-tlnt=t where t is not equal to zero.

Hence,the wronskian  is not equal to zero .Therefore, the set of solutions is independent.

Hence, the set {t , tln t} form a fundamental set of solutions for given equation.

6 0
3 years ago
HELP PLEASE and show work
larisa86 [58]

Answer:

\boxed{\stackrel{\Large\frown}{PQS}\:= 222°}

Explanation:

Since \overline{PR} is a diameter, arc \stackrel{\Large\frown}{PQR}\:= 180°.

Given that \angle{SUR} = 42° is a subtended central angle by two diameters,

\stackrel{\large\frown}{RS} \:= 42°.

Using the rule of arcs, \stackrel{\Large\frown}{PQR} + \stackrel{\large\frown}{RS} \: = \: \stackrel{\Large\frown}{PQS} →

180° + \: 42° = \: \stackrel{\Large\frown}{PQS}

222° = \: \stackrel{\Large\frown}{PQS}

\stackrel{\Large\frown}{PQS} \: = \: 222°

3 0
3 years ago
a car costs 25,750.00 and depreciates in value 20%per year. how much will the car be worth in 5 years?
andriy [413]
In five years the car will be worth $9,472.90
3 0
3 years ago
Given six memory partitions of 300 kb, 600 kb, 350 kb, 200 kb, 750 kb, and 125 kb (in order, how would the first-fit, best-fit,
NNADVOKAT [17]

Answer:

Step-by-step explanation:

first fit:

115 -> 300

500-> 600

358 -> 750

200 -> 350

375 -> not able to allocate  

Best fit:

115 -> 125

500 -> 600

358 -> 750

200 -> 200

375 -> not able to allocate

worst fit:

115 -> 750

500 -> 600

358 -> not able to allocate

200 -> 350

375 -> not able to allocate

6 0
3 years ago
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