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3 years ago

A triangle has a base length given by the equation b = 2x + 4 and a height given by the equation h

Mathematics

1 answer:

Anna11 [10]3 years ago

7 0

It’s 230 I hope this helps

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Law of cosines.Anyone good in Trigonometry?

marin [14]

Answer:

$c=11.8\ units$

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

$c^2=a^2+b^2-2(a)(b)cos(C)$

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

$a=3\ units\\b=10\ units$

$C=120^o$

substitute the given values

$c^2=3^2+10^2-2(3)(10)cos(120^o)$

$c^2=109-(60)cos(120^o)$

$c^2=109-(60)(-0.5))$

$c^2=109+30$

$c^2=139$

$c=11.8\ units$

3 0

2 years ago

Which best describes a transformation that preserves the size, shape, and angles of an object? A. congruent transformation B. no

Harrizon [31]

Answer:

Your answer would be D: isometry

Step-by-step explanation:

6 0

2 years ago

Can someone help me on this question.

Temka [501]

46! Because 5 times 3 is 15 and the two big rectangles are equal, that’s 15+15. (30) 5x1 is 5 and THERES two equal things like that so 5+5 (10). 3x1 is 3 and THERES also two equal things so add 3+3. (6) add 30+10+6 which makes 46! :)

7 0

3 years ago

Read 2 more answers

Find the value of root 121 + 3 over root 125

NemiM [27]

Answer:

$\mathrm{Decimal:\quad }\:1.25219\\\frac{14\sqrt{5}}{25}$

Step-by-step explanation:

$\frac{\sqrt{121}+3}{\sqrt{125}}\\\sqrt{125}=5\sqrt{5}\\=\frac{\sqrt{121}+3}{5\sqrt{5}}\\\sqrt{121}=11\\=\frac{11+3}{5\sqrt{5}}\\\mathrm{Add\:the\:numbers:}\:11+3=14\\=\frac{14}{5\sqrt{5}}\\\mathrm{Rationalize\:}\frac{14}{5\sqrt{5}}:\quad \frac{14\sqrt{5}}{25}\\=\frac{14\sqrt{5}}{25}$

7 0

3 years ago

Read 2 more answers

Tell whether the sequence is arithmetic. If the sequence is arithmetic, write a function rule to represent it.

fredd [130]

Answer:

A. no

Step-by-step explanation:

I hope it help............

8 0

2 years ago