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Vadim26 [7]
3 years ago
13

In the theory of learning, the rate at which a subject is memorized is assumed to be proportional to the amount that is left to

be memorized. suppose m denotes the total amount of a subject to be memorized and a(t) is the amount memorized in time t > 0. determine a differential equation for the amount a(t). (assume the constant of proportionality is k > 0. use a for a(t).)

Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0

The answer is in the picture, I can't add it.

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What is the sum of 10/12and 11/12? Make sure to show all work to receive full credit!
sergiy2304 [10]

Answer:

1\frac{3}{4}

Step-by-step explanation:

\frac{10}{12} +\frac{11}{12} \\\\\frac{21}{12} \\\\1\frac{9}{12} \\\\1\frac{3}{4}

7 0
3 years ago
Rewrite the following 7(3+5=___+___​
Ray Of Light [21]

Answer:

21+35

Step-by-step explanation:

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2 years ago
What are the next three terms in the pattern 2, 6, 18, 54, ...?
castortr0y [4]

Answer:

OPTION B: 162, 486, 1458

Step-by-step explanation:

The given sequence is 2, 6, 18, 54, . . .

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Here a = 2 and r = 3.

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8 0
2 years ago
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-4+2(12)<br> ————<br> -3(-3)-(-1)
dsp73

Answer:

20/10 is 2

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8 0
3 years ago
Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
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