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3 years ago

Explain how you could determine whether a calculator correctly performs the order of operations

Mathematics

2 answers:

Eva8 [605]3 years ago

5 0

Use photo math it shows you the steps it takes to get the answer.

Talja [164]3 years ago

3 0

You could always do your work on a piece of paper and compare answers.

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What is the least common multiple of the denominatiors for the two fractions 1/6 and 5/8

aksik [14]

Answer:

$24$

Step-by-step explanation:

6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60

8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80

If you list out the multiples of 6 and 8 you will find that the least common multiple is 24.

7 0

4 years ago

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max2010maxim [7]

Answer:

bbhwhehwyayyquqysyegegegsgsgsgsusus

Step-by-step explanation:

vgsgahah z z zb

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3 years ago

If x(f) = x5 and g(x) = -2-3x2 , which is f(g(x))

mel-nik [20]

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4 years ago

Figure VWYX is a kite. What is the value of x?

Alecsey [184]

Answer:

$x=6\°$

Step-by-step explanation:

we know that

The sum of the internal angles of a kite is equal to $360\°$

In this problem we have

$90\°+90\°+(18x-2)\°+(12x+2)\°=360\°$

$(18x-2)\°+(12x+2)\°=360\°-180\°$

$30x=180\°$

$x=6\°$

8 0

3 years ago

Read 2 more answers

If U = {x: X € N, 1 < × < 15)

Inessa05 [86]

Answer:

Step-by-step explanation:

Given:

U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

A = {2,4,6,8,10,12,14}

B = {3,6,9,12,15}

C = {5,10,15}

(a) Verify A(BnB)=(AUB)(AUB)

A U (B n B)

= {2,4,6,8,10,12,14} U ( {3,6,9,12,15} n {3,6,9,12,15} )

= {2,4,6,8,10,12,14} U {3,6,9,12,15}

= {2,3,4,6,8,9,10,12,14,15}

( A U B) n (A U B)

= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}

= {2,3,4,6,8,9,10,12,14,15}

Therefore

A U (B n B) = ( A U B) n (A U B)

verifies

(b) Verify An(BUC)=(AnB)u(AnC)

A n ( B U C)

= {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )

= {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}

= {6,10,12}

( A n B ) U ( A n C )

= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )

= {6,12} U {10}

= {6,10,12}

Therefore

A n ( B U C) = ( A n B ) U ( A n C )

verifies

AU(BUC)

= {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}

= {2,3,4,5,6,8,9,10,12,14,15}

(AUB)U(AUC)

= ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})

= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}

= {2,3,4,5,6,8,9,10,12,14,15}

Therefore

AU(BUC)=(AUB)U(AUC)

verifies

5 0

3 years ago