Select the correct answer.

What happens it the offshore team members are not able to participate in the iteration demo due to time zone/infrastructure issu

professor190 [17]

The best option that will suite is that there will be no major issues since the offshore leads and the onsite members participated in the demo with the Product Owner/Stakeholders they can cascade the feedback to the offshore members

Explanation:

Iteration demo is the review which is done to gather the immediate feedback from the stakeholders on a regular basis from the regular cadence. This demo will be one mainly to review the progress of the team and the and to cascade and show their working process

They show their working process to the owners and they and the other stakeholders and they get their review from them and so there will be no issues if the members are not able to participate

5 0

3 years ago

Rows within a spreadsheet are identified by:

EleoNora [17]

Answer:

Option C: Numbers.

Explanation:

By default, rows within a spreadsheet are identified by Numbers i.e. 1,2,3,............

Total rows are 1048575 in one spreadsheet.

7 0

3 years ago

Assume in the for loop header, the range function has the three arguments: range (1, 10, 3), if you were to print out the value

Licemer1 [7]

Answer:

1, 4, 7

Explanation:

The instruction in the question can be represented as:

for i in range(1,10,3):

print i

What the above code does is that:

It starts printing the value of i from 1

Increment by 3

Then stop printing at 9 (i.e.. 10 - 1)

So: The sequence is as follows

Print 1

Add 3, to give 4

Print 4

Add 3, to give 7

Print 7

Add 3, to give 10 (10 > 10 - 1).

So, it stops execution.

6 0

2 years ago

Write code for a function with the following prototype: /* Addition that saturates to TMin or TMax */ int saturating_add(int x,

Kazeer [188]

Answer:

See explaination

Explanation:

program code.

/* PRE PROCESSOR DIRECTIVES */

#include<stdio.h>

/* PRE-DEFINED VALUES FOR TMAX AND TMIN */

#define TMax 2147483647

#define TMin (-TMax -1)

/* saturating_add(int,int) METHOD IS CALLED HERE */

int saturating_add(int firstNumber, int secondNumber)

{

/*

FOR BETTER UNDERSTANDING, LETS TAKE TEST CASE,

WHERE firstNumber = 5 AND secondNumber = 10

*/

int w = sizeof(firstNumber) << 3;

/*

sizeof(firstNumber) VALUE IS 4, SO USING BINARY LEFT SHIFT OPERATOR TO THREE PLACES,

WE HAVE NOW VALUE 32, ASSIGNED TO w

*/

/* ADDITION IS CALCULATED => 15 */

int addition = firstNumber + secondNumber;

/*

MASK INTEGER VARIABLE IS TAKEN

mask BIT IS LEFT SHIFTED TO 31 PLACES => 2^31 IS THE NEW VALUE

*/

int mask = 1 << (w - 1);

/* FIRST NUMBER MOST SIGNIFICANT BIT IS CALCULATED BY USING AND OPERATOR */

int msbFirstNumber = firstNumber & mask;

/* SECOND NUMBER MOST SIGNIFICANT BIT IS CALCULATED BY USING AND OPERATOR */

int msbSecondNumber = secondNumber & mask;

/* MOST SIGNIFICANT BIT OF ADDITION IS CALCULATED BY USING AND OPERATOR */

int msbAddition = addition & mask;

/* POSITIVE OVERFLOW IS DETERMINED */

int positiveOverflow = ~msbFirstNumber & ~msbSecondNumber & msbAddition;

/* NEGATIVE OVERFLOW IS DETERMINED */

int negativeOverflow = msbFirstNumber & msbSecondNumber & !msbAddition;

/* THE CORRESPONDING VALUE IS RETURNED AS PER THE SATURATING ADDITION RULES */

(positiveOverflow) && (addition = TMax);

(negativeOverflow) && (addition = TMin);

return addition;

}

/* MAIN FUNCTION STARTS HERE */

int main(){

/* TEST CASE */

int sum = saturating_add(5, 10);

/* DISPLAY THE RESULT OF TEST CASE */

printf("The Sum Is : %d\n\n",sum);

}

7 0

3 years ago

Given: an int variable k, an int array current Members that has been declared and initialized, an int variable memberID that has

Alekssandra [29.7K]

Answer:

The c++ program is given below. Nothing is displayed as per the question.

#include <iostream>

using namespace std;

int main() {

// declaration and initialization of integer variables

int k, memberID = 12, nMembers=5;

bool isAMember;

// declaration and initialization of integer array

int currentMembers[] = {12, 34, 56, 78, 90};

for(k=0; k<nMembers; k++)

{

if(memberID == currentMembers[k])

{

// when member is found in the array, the loop is exited using break

isAMember = true;

break;

}

else

isAMember = false;

}

return 0;

}

Explanation:

The program begins with declaration and initialization of integer variables and followed by initialization of the array holding the id of all the members.

The Boolean variable is declared but not initialized.

int k, memberID = 12, nMembers=5;

bool isAMember;

int currentMembers[] = {12, 34, 56, 78, 90};

After this, the array holding the id of the members is searched for the given member id. This is done using a for loop and a if else statement inside the loop.

If the member id is present in the array, the variable isAMember is initialized to true otherwise it is assigned false.

When the variable isAMember is initialized to true, the break statement is used to exit from the loop.

for(k=0; k<nMembers; k++)

{

if(memberID == currentMembers[k])

{

isAMember = true;

break;

}

else

isAMember = false;

}

The break is used since other values of id in the array will not match the given member id and the variable, isAMember will be initialized to false even if the given member id is present in the array. Hence, it is mandatory to exit the loop once the given member id is found in the array.

This program can be tested for different values of the id of the members and different sizes of the array.

4 0

3 years ago