Answer:
Yes prison breeds criminal minds
Step-by-step explanation:
When you send a person to a house filled with just criminals they will just become more criminal minded. If they spend a long time in the prison system too the person will forget how life outside was. It will be like sending a child into the outside world except with a ton of knowledge on how to rob and stuff like that.The american prison system is one of the shadiest systems to be created in my opinion.Its a system built for you to come back over and over.Usually when you get out u have less opportunities for a job.Forget about having a career if you went to prison for literally anything.Your family might disown you or forget you. Its just heartbreaking to see prisoners come out of jail just to have even less opportunity to change their life than before they went. It will get to a point where you need to do crime to survive or live comftorably on the outside world. The american prison system is just built to get revenge on someone and ruin their whole life. I know some European countries have an amazing prison system where they fix you and give you opportunities to become better. Thing is in america we dont want to help the guy that scammed or killed a friend of ours. We just end up hoping their life is miserable and thats our prison system.Its absolutely disgusting.Instead of heavily punishing these people and sending them into the world without help. We should help them and make them better people for our society.Im sorry if this is very disorganized and hard to understand i just wrote what my mind blurted into this keyboard
Answer:
Solve the rational equation by combining expressions and isolating the variable
x
.
All real numbers
Interval Notation:
−∞,∞)
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
Plug in one to the equation to get (1)^3 - 2(1)^2, 1 to the power of anything is 1 so it boils down to 1-2, which is -1
Answer:
b(b/a)^2
Step-by-step explanation:
Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then
b = a - (p% × a) = a(1-p%)
b/a = 1 - p%
p% = 1 - b/a = (a-b)/a
Let the worth of the car on December 31, 2012 be c
then
c = b - (b × p%) = b(1-p%)
Let the worth of the car on December 31, 2013 be d
then
d = c - (c × p%)
d = c(1-p%)
d = b(1-p%)(1-p%)
d = b(1-p%)^2
d = b(1- (a-b)/a)^2
d = b((a-a+b)/a)^2
d = b(b/a)^2 = b^3/a^2
The car's worth on December 31, 2013 = b(b/a)^2 = b^3/a^2
Answer:
the answer is positive.but just know that this aint a wuestion
Step-by-step explanation:
there are no calculations
