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murzikaleks [220]
3 years ago
12

I NEED HELP ASAP! WILL MARK YOU AS BRAINLIEST!

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0

Coordinate of C;

( \frac{(1 - 3)}{2} , \frac{(2 - 4)}{2} )

apply the formulae, replace the variables with the given values.

Slope;

m =  \frac{(4 - 2)}{(3 - 1)}

again, apply the formulae, replace the variables with the given values.

calculate it urself, ive done enough

atroni [7]3 years ago
4 0

Answer:

Answers below in bold.

Step-by-step explanation:

Midpoint formula:

(\frac{1+3}{2} , \frac{4+2}{2} )=

(\frac{4}{2} , \frac{6}{2} )=

(2, 3)

Point C is on the point (2, 3)

Slope:

\frac{4-2}{3-1} =

\frac{2}{2}=

1

The slope is going at y=x+1

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PLSSS HELP ASAPPP I'LL GIVE YOU BRAINLIEST IF I GET IT RIGHT!!!​
kondor19780726 [428]

Answer:

D. 76

Step-by-step explanation:

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3 0
3 years ago
Several years​ ago, 50​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that​ parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 1095, \pi = \frac{478}{1095} = 0.4365

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that​ parents' attitudes toward the quality of education have changed.

5 0
3 years ago
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solve. PEMDAS
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Multiplication & Division second (left to right)
100.48+125.6
Add & Subtract (left to right)
226.08cm

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4 0
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