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Wewaii [24]
3 years ago
9

A circular flower bed is 16 m in diameter and has a circular sidewalk around it that is 2 m wide. Find the area of the sidewalk

in square meters. Use 3.14 for pi.
The area of the sidewalk is _____ m^2
Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0
The correct anwser is 113
Katyanochek1 [597]3 years ago
7 0
59.69 is probably the answer. let me know.
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Find the length of the radius of the following circle. (x + 2)2 + y2 = 10 5 √(10) 100
Makovka662 [10]

<span>For this case we have the following equation:</span>

<span> (x + 2) 2 + y2 = 10</span>

<span> We must remember that the standard equation of the circle is given by:</span>

<span> (x - h) 2 + (y - k) 2 = r2</span>

<span> Where r is the radius.</span>

<span> Therefore, in the given equation the radius is:</span>

<span> r ^ 2 = 10</span>

<span> Clearing we have:</span>

<span> R = root (10)</span>

<span> Answer:</span>

<span> The length of the radius of the circle is:</span>

<span><span> √ (10)</span></span>

5 0
3 years ago
Read 2 more answers
Write an equation in point slope and slope intercept form of a line that passes through the given point and has the given slope
Evgesh-ka [11]

Answer:

Point-Slope: y+4=-\frac{1}{2}(x+3)

Slope-Intercept: y=-\frac{1}{2}x-\frac{11}{2}

Step-by-step explanation:

The point-slope formula is y-y_{1}=m(x-x_{1}  ). The slope-intercept formula is y=mx+b. Since we are given the point and slope, we can directly plug it into the point-slope formula.

Point-Slope

y-(-4)=-\frac{1}{2}(x- (-3))

y+4=-\frac{1}{2} (x+3)

To find the slope-intercept form, we can manipulate the point-slope form to get the slope-intercept form.

Slope-Intercept

y+4=-\frac{1}{2}x-\frac{3}{2}

y=-\frac{1}{2}x-\frac{11}{2}

6 0
3 years ago
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Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m = 1/2?
Jobisdone [24]
The correct equation is y=1/2x-21
8 0
3 years ago
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A similarity transformation maps `Delta`ABC to `Delta`JKL. The measure of `/_A` of preimage `Delta`ABC is 105°. The scale factor
RoseWind [281]

Please note that dilation does not affect angles. Thus, if an image is dilated the angle remains the same and does not change.

Therefore, even if \Delta ABC is dilated to \Delta JKL by a factor of 1.5 (or by any factor for that matter), the linear dimensions of the original triangle \Delta ABC will either get stretched or get shrunk by a factor of 1.5 but the angles of the original triangle will not be affected in any case.

Please note that this is true for all two dimensional geometric shapes.

5 0
3 years ago
Please help me find the answer to:<br>12x^5 ÷ 3x^2
Ivahew [28]
Graph for 12*X^5/ (3*X^2)

4 0
2 years ago
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