A is 14 total
B is yes because the gained 11 and lost 3 which means they gained 8 after taking away the ones lost and they are still on the positive side so they keep th ball.
Answer:
We are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%
Step-by-step explanation:
We are given that in a group of randomly selected adults, 160 identified themselves as executives.
n = 160
Also we are given that 42 of executives preferred trucks.
So the proportion of executives who prefer trucks is given by
p = 42/160
p = 0.2625
We are asked to find the 95% confidence interval for the percent of executives who prefer trucks.
We can use normal distribution for this problem if the following conditions are satisfied.
n×p ≥ 10
160×0.2625 ≥ 10
42 ≥ 10 (satisfied)
n×(1 - p) ≥ 10
160×(1 - 0.2625) ≥ 10
118 ≥ 10 (satisfied)
The required confidence interval is given by

Where p is the proportion of executives who prefer trucks, n is the number of executives and z is the z-score corresponding to the confidence level of 95%.
Form the z-table, the z-score corresponding to the confidence level of 95% is 1.96







Therefore, we are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%
Any number inside the modulus sign becomes positive. This means
and so we have,

Solving these gives us


However if we check the second solution in the original equation we obtain
. This is false and so
can't be a solution.
Therefore the only solution is
.
(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)
I assume you mean 9+52,
If so you can add the 9 and the 2 together:
9+2 = 11
Then you can add the 11 on to the 50 to get the final answer:
50+11 = 61
Hope this helps! :)
Answer:
A
Step-by-step explanation:
vertical angles congrunet (angleFJH + angle GJI)
& (angleHFJ + angle JGI congruent)