Answer:
segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13
Step-by-step explanation:
Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).
1. Reflection over x = 1 maps vertices A, B and C as follows
- A(-3,3)→A'(5,3);
- B(1,-3)→B'(1,3);
- C(-3,-3)→C'(5,-3).
2. Dilation by a scale factor of 2 from the origin has the rule
(x,y)→(2x,2y)
So,
- A'(5,3)→A''(10,6);
- B'(1,3)→B''(2,6);
- C'(5,-3)→C''(10,-6)
See attached diagram for details
Note that
so
Answer:
(a) 7.5 seconds
(b) The horizontal distance the package travel during its descent is 1737.8 ft
Step-by-step explanation:
(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀
The initial height of the object s₀ = 900 feet
The initial vertical velocity of the object v₀
= 0 m/s
The time it takes the package to strike the ground is found as follows;
0 = -16·t² + 0×t + 900
900 = 16·t²
t² = 900/16 = 62.25
t = √62.25 = 7.5 seconds
(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have
158 miles/hour = 231.7126 ft/s
The horizontal distance the package covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place
The horizontal distance the package travel during its descent = 1737.8 ft.
Answer: During the second hour it could travel either 4,5,6,7,8,9 hours
Step-by-step explanation:
Answer:
Step-by-step explanation:
x=3
