1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex17521 [72]
3 years ago
7

There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin

ux, and 345 have taken a course in C. Further, 876 have taken courses in both Java and Linux, 231 have taken courses in both Linux and C, and 290 have taken courses in both Java and C. If 189 of these students have taken courses in Linux, Java, and C, how many of these 2504 students have not taken a course in any of these three subjects?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

You might be interested in
Math is hard and suckssssssssssssssss
inessss [21]

Answer:

X=7

Hope it was helpful

Step-by-step explanation:

Good luck ^___^

4 0
2 years ago
Use the digits 2, 3, and 5 to create a fraction and a whole number with a product greater than 2
kupik [55]
The fractions which cannbe formed are: 2/3, 3/2, 2/5, 5/2, 3/5 and 5/3.
Now, we find the products with the third number:
2/3*5= 10/3 = 3.33 > 2
3/2*5 = 15 >2= 7.5 > 2
2/5*3= 6/5 (rejected)
5/2*3 = 15/2 > 2
3/5*2= 6/5 (rejected)
5/3*2 = 15/2 = 7.5> 2
5 0
3 years ago
Read 2 more answers
NEEED HELPppppppppppp<br> PLSSSSS
Sunny_sXe [5.5K]

Answer:

probably the furthest graph to the left.

Step-by-step explanation:

seems like a 25% 10% split.

7 0
2 years ago
2 A change in the genes of a species over a<br> long period of time.
Blizzard [7]

Answer:

There is no question..?

3 0
2 years ago
Read 2 more answers
1 2/3 + 1/8 <br> Can you help pls <br> Nowww pls
Likurg_2 [28]

Answer:

Step-by-step explanation:

43/24

or

1  19/24

7 0
2 years ago
Read 2 more answers
Other questions:
  • A fee of 12.50 is deducted each month from Aubryn's bank account. She currently has a balance of $75.00 in her account. She must
    12·1 answer
  • Graph the following linear equation. y=-5/2x+10
    14·1 answer
  • Four polynomials are shown below:
    7·2 answers
  • If r(x)=3x-1 and s(x)=2x+1, which expression is equivalent to (r-s)(6)
    10·1 answer
  • please help me its due at 3:00 and i'm crying and i cant stop please please help. 30 points make sure its right for me thanks
    15·2 answers
  • at the zoo,there were 3 times as many monkeys as lions.tom counted a total of 24 monkeys and lions.how many monkeys were there
    12·1 answer
  • Which percent is equal to the given fraction? <br><br><br> 1/20
    8·2 answers
  • Out of the 30 days in April, 3/5 of the days were sunny and clear. The rest of the days were either cloudy or contained some rai
    9·1 answer
  • The endpoints of a side of rectangle ABCD in the coordinate plane are at A (1,7) and
    8·1 answer
  • NEED HELP FAST PLEASE
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!