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Dmitriy789 [7]
2 years ago
11

If P(A)=0.4, P(A and B)=0.2,and P(A or B)=0.5, What is P(B)

Mathematics
1 answer:
Vladimir [108]2 years ago
6 0

Answer:

\boxed{\ P(B)=0.3 \ }

Step-by-step explanation:

Hi,

We know that

P(A or B)=P(A)+P(B)-P(A and B)

so P(B)= P(A or B) - P(A) + P(A and B)

so

P(B) = 0.5 - 0.4 + 0.2 = 0.3

thanks

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The odds of flipping a fair coin either heads or tails is 50%. The odds of rolling a six on a fair six sided die is 16.6% or 1 i
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P( sum is prime )= 73/216

Step-by-step explanation:

The minimum value of the sum will be 3 and maximum value will be 18. So the prime numbers in this range are 3 , 5, 7, 11, 13, 17.

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A government bureau publishes annual price figures for new mobile homes. A simple random sample of 36 new mobile homes yielded t
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Answer:

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The prices in thousands of dollar are:</em>

<em>66.6, 69.8, 58.4, 57.3, 63.1, 61.8, 56, 72.7, 61.8,  </em>

<em>66.9, 72.6, 63.1, 58.7, 65.9, 61.1, 56.1, 49.9, 72.6,  </em>

<em>49, 56.4, 72.6, 60.1, 65, 64.8, 56.5, 52, 53.2,  </em>

<em>56.4, 75.4, 76.3, 60.5, 74.6, 57, 69.2, 62.7, 77.2.</em>

<em />

We have a sample of n=36 new mobile homes.

The mean of this sample is:

M=(1/36)\sum_{i=1}^{36}x_i=\dfrac{2273.3}{36}=63.147

The population standard deviation is σ=7.5 (in thousands of dollars).

The critical value of z for a 99.7% CI is z=2.97.

Then, we can calculate the margin of error as:

E=z\cdot \sigma/\sqrt{n}=2.97*7.5/\sqrt{36}=22.275/9=2.475

Now we can calculate the lower and upper bound of the confidence interval as:

LL=\bar X-E=63.147-2.475=60.672\\\\UL=\bar X+E=63.147+2.475=65.622

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

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