To answer this i need a little more info but it's probably going to be 30 miles.
a) The factors have the form:

where x1 is a zero of the function. A zero is a point at which the graph intercepts the x-axis. From the graph, the zeros are:
-6, -4, 2, and 3
Therefore, the factors are:
(x + 6)
(x + 4)
(x - 2)
(x - 3)
b) Multiplying all these factors we get a polynomial, p(x), with the zeros of the graph. That is:
p(x) = (x + 6)(x + 4)(x - 2)(x - 3)
c) Yes, it is possible to find other polynomials with the same zeros. To do that we have to multiply p(x) by a constant. For example, multiplying by 2:
f(x) = 2(x + 6)(x + 4)(x - 2)(x - 3)
and f(x) has the same zeros as p(x)
d) Every polynomial obtained in the previous way, multiplying p(x) by a constant, will have a different graph. In conclusion, it is not possible to find other polynomials with the same zeros and the same graph.
Answer: -ab - 11a^2 - 3b + 3a
Step-by-step explanation:
i think this is what you're wanting? if not just comment what you need and i'll retry it!
There is no question mark in the question
and the statement is true
First see how many times 80 goes in to 400 and then see what you have left and that’s how many commercials her song was in