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Ipatiy [6.2K]
3 years ago
7

All rhombuses are parallelograms, but not all parallelograms are rhombuses. What attribute does a rhombus have that a parallelog

ram does not? A) 4 congruent sides B) 2 sets of opposite parallel sides C) 2 sets of opposite congruent angles D) 4 angles that have a sum of 360°
Mathematics
2 answers:
omeli [17]3 years ago
8 0
The answer is:  [C]:  "2 sets of opposite congruent angles" .
______________________________________________________
{<u><em>Note</em></u>: 
All squares are rhombuses; but not all rhombuses are squares.
All squares are parallelograms, but not all parallelograms are squares.
All squares are rectangles, but not all rectangles are squares.                                       All rectangles are parallelograms, but not all parallelograms are rectangles.}.
_______________________________________________________
spin [16.1K]3 years ago
3 0
C. 2 sets of opposite congruent angles
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6/9 in two different forms
maw [93]
Word form: Six over nine or two over three

Simpliest form: 2/3
3 0
3 years ago
Pls help me guys! This is super hard
Mashcka [7]
I count 4 green stars and 6 red stars

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4 green : 6 red

4:6

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2:3
6 0
3 years ago
Read 2 more answers
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
3 years ago
one x-intercept for a parabola is at the point (2, 0). use the quadratic formula to find the other x-intercept for the parabola
omeli [17]

Answer:

Step-by-step explanation:

There are 3 ways to find the other x intercept.

1) Polynomial Long Division.

Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.

2) Just solving for x when y = 0, by using the quadratic formula.

x^2 - 3x + 2 = 0\\x_{12} = \frac{3 \pm \sqrt{9 - 4(1)(2)}}{2} = \frac{3 \pm 1}{2} = 2, 1.

So the other x - intercept is at (1, 0)

3) Using Vietta's Theorem regarding the solutions of a quadratic

Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.

x_1 + x_2 = \frac{-b}{a}

And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.

x_1 \cdot x_2 = \frac{c}{a}

These relations between the solutions give us a brief idea of what the solutions should be like.

6 0
3 years ago
How to turn this equation: <br> y= -1.02(x-3)^2+9.25<br> into factored form
MatroZZZ [7]

Answer:

y=(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})

Step-by-step explanation:

You first equate it to zero to get:

-1.02(x-3)^2+9.25=0

Then solve using square root method

-1.02(x-3)^2=-9.25

(x-3)^2=\frac{-9.25}{-1.02}

(x-3)^2=\frac{925}{102}

x=3\pm\sqrt{\frac{925}{102}}

Or

x=3\pm{\frac{5\sqrt{3774}}{102}}

x={\frac{306\pm5\sqrt{3774}}{102}}

Now work it backwards

102x-(306\pm5\sqrt{3774})=0

(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})=0

Hence the factored form is:

y=(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})

8 0
3 years ago
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