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svlad2 [7]
3 years ago
14

Which sheep has a larger area of rectangle that is 7" by 3 fourths inch or a square with side length of 2 1/2 inches

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0
If you multiply 7 by .75 you get 5.25
rectangle = area = 5.25
then multiply 2.5 by itself and you get 6.25
square area = 6.25
So the 2 1/2 inch square has more room
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Charles is 19 years old. his grandfather is 67 years older than he. what was thee total age 9 years ago?
almond37 [142]
Today: x=19
y=67+19=86

9 years ago: x=19-9=10
y=86-9=77

The total age 9 years ago: x+y=10+77=87
3 0
3 years ago
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I will gove ppints to anybody who answers this because you will deserve it thank you
kkurt [141]
\left(4^4\right)^2=4^8=65536\\

5 0
2 years ago
What is the value ofx in the equation 2(6x+4)-6+2x=3(4x+3) + 1<br> 1<br> 3<br> 4<br> 6
ira [324]

Answer:

x = 4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Equality Properties
  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define Equation</u>

2(6x + 4) - 6 + 2x = 3(4x + 3) + 1

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                   12x + 8 - 6 + 2x = 12x + 9 + 1
  2. Combine like terms:                   14x + 2 = 12x + 10
  3. Subtract 12x on both sides:       2x + 2 = 10
  4. Subtract 2 on both sides:          2x = 8
  5. Divide 2 on both sides:              x = 4
8 0
3 years ago
The pesticide diazinon is in common use to treat infestations of the German cockroach, Blattella germanica. A study investigated
cluponka [151]

Answer:

We conclude that there is no difference in the proportion of cockroaches that died on each surface.

Step-by-step explanation:

We are given that a study investigated the persistence of this pesticide on various types of surfaces.

After 14 days, they randomly assigned 72 cockroaches to two groups of 36, placed one group on each surface, and recorded the number that died within 48 hours. On the glass, 18 cockroaches died, while on plasterboard, 25 died.

<em>Let </em>p_1<em> = proportion of cockroaches that died on glass surface.</em>

<em />p_2<em> = proportion of cockroaches that died on plasterboard surface.</em>

So, Null Hypothesis, H_0 : p_1-p_2 = 0      {means that there is no difference in the proportion of cockroaches that died on each surface}

Alternate Hypothesis, H_A : p_1-p_2\neq 0      {means that there is a significant difference in the proportion of cockroaches that died on each surface}

The test statistics that would be used here <u>Two-sample z proportion</u> <u>statistics</u>;

                       T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}  } }  ~ N(0,1)

where, \hat p_1 = sample proportion of cockroaches that died on glass surface = \frac{18}{36} = 0.50

\hat p_2 = sample proportion of cockroaches that died on plasterboard surface = \frac{25}{36} = 0.694

n_1 = sample of cockroaches on glass surface = 36

n_2 = sample of cockroaches on plasterboard surface = 36

So, <u><em>test statistics</em></u>  =  \frac{(0.50-0.694)-(0)}{\sqrt{\frac{0.50(1-0.50)}{36}+\frac{0.694(1-0.694)}{36}  } }

                               =  -1.712

The value of z test statistics is -1.712.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no difference in the proportion of cockroaches that died on each surface.

8 0
3 years ago
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madreJ [45]

Answer:

Where is the question?

Step-by-step explanation:

5 0
3 years ago
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