The answer to your question is 9,9
keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of that line above anyway,
![\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{2+1}{3}\implies 1 \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B-1%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B2%7D-%5Cstackrel%7By1%7D%7B%28-1%29%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B4%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B2%2B1%7D%7B3%7D%5Cimplies%201%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
so we're really looking for the equation of a line whose slope is -1 and runs through (2,5)
Answer:
<h2>x = 2 </h2><h2>y = - 3</h2><h2>z = - 2</h2>
Step-by-step explanation:
6y - 5z = -8 .......... Equation 1
3z = -6 ................... Equation 2
4x - 3y - 2z= 21...... Equation 3
<u>First solve for z in Equation 2</u>
That's
3z = - 6
Divide both sides by 3
<h3>z = - 2</h3>
Next substitute the value of z into Equation 1 in order to find y
We have
6y - 5(-2) = - 8
6y + 10 = - 8
6y = - 8 - 10
6y = - 18
Divide both sides by 6
<h3>y = - 3</h3>
Finally substitute the values of y and z into Equation 3 to find the value of x
That's
4x - 3(-3) - 2(-2) = 21
4x + 9 + 4 = 21
4x + 13 = 21
4x = 21 - 13
4x = 8
Divide both sides by 4
<h3>x = 2</h3>
So the solutions are
<h3>x = 2 </h3><h3>y = - 3</h3><h3>z = - 2</h3>
Hope this helps you
Answer: 30p
Step-by-step explanation:
Cost of donuts in the first shop £1.20
Cost at the second shop at 25% higher
= 1.20 x 1.25 = 1.50
Difference in price
= 1.50 - 1.20 = 0.30
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