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Ad libitum [116K]
3 years ago
6

What is the equation of a line with slope of 3 and a y-intercept of 12?

Mathematics
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

y=3x+12

Step-by-step explanation:

The slope intercept form of the equation is y=mx+b where m is the slope and b is the y-intercept. This means b=12 and m=3.

y=3x+12

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What is one light year in seconds need it to written out in the conversion format
ra1l [238]

In one year there are 365 days of 24 hours. Each hour has 60 minutes and each minute is 60 seconds long. So, 60s/min x 60 min/hr x 24hr/day x 365 days equals 31,536,000s.


Hope this helps you with your answer. If it is incorrect, then I am sorry.

8 0
3 years ago
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State whether the following statement is true or​ false, and explain why. If the statement is​ false, state the true change. A h
katovenus [111]

Answer:

False

Step-by-step explanation:

Given that a high school reports that its​ students' SAT scores were down by 12​% in one year. The next​ year, however, the test scores rose by 20​%.

Let score initially be 100

Down by                     12

Next year score         88

For succeedingyear

increase is 20%        =20% of 88=17.6\\

Score in the 2nd year = 88+17.6 = 105.6

Hence overall scores improvement is 5.6% and not 8%

5 0
3 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
3 years ago
Suppose $1750 is put into an account that pays an annual rate of 4.5%
Yanka [14]

Answer:

The amount in the account after six years is $2,288.98

Step-by-step explanation:

In this question, we are asked to calculate the amount that will be in an account that has a principal that is compounded quarterly.

To calculate this amount, we use the formula below

A = P(1+r/n)^nt

Where P is the amount deposited which is $1,750

r is the rate which is 4.5% = 4.5/100 = 0.045

t is the number of years which is 6 years

n is the number of times per year, the interest is compounded which is 4(quarterly means every 3 months)

we plug these values into the equation

A = 1750( 1 + 0.045/4)^(4 * 6)

A = 1750( 1 + 0.01125)^24

A = 1750( 1.01125)^24

A = 2,288.98

The amount in the account after 6 years is $2,288.98

6 0
3 years ago
PLEASE HELP!!!!!!!!!!AND READ ALL PLEASE
Scrat [10]
It terminates <span>9÷16=<span>.5625</span></span>
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3 years ago
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