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lana66690 [7]
3 years ago
14

A group of 8 students was asked, "How many hours did you watch television last week?" Here are their responses: 7, 20, 8, 15, 10

, 17, 7, 13 Find the mean and median number of hours for these students. If necessary, round your answers to the nearest tenth.
Mathematics
2 answers:
cestrela7 [59]3 years ago
5 0
Well, lets find the Median first. Putting the numbers in order from least to greatest (7,7,8,10,13,15,20) then count from each side to find the middle number (15). To find the Mean you will add all of the numbers together and divide by how many numbers there are so 7+7+8+10+13+15+20=80. We then do 80/7=11.4, rounded will be 11.0.

Mean: 11
Median: 15

I hope this helped!
Musya8 [376]3 years ago
3 0
To find the mean you add up all the numbers and divide that amount by the amount of numbers. Which looks like this:
7 + 20 + 8 + 15 + 10 + 17 + 7 + 13= 97
97 divided by 8 = 12.125

The mean is 12.125.

To find the median you first need to put the numbers in order and then try to find the number in the middle. If there is two numbers in the middle those two numbers are still the median:
7, 7, 8, 10, 13, 15, 17, 20, 

The median(s) are 10 and 13. 
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In the year 2001, a company made $7.2 million in profit. For each consecutive year after that, their profit increased by 11%. Ho
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2 years ago
Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf
kobusy [5.1K]

Answer:

(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}

And replacing we got:

(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903

(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097

And the confidence interval for the difference of means would be given by:

0.2903 \leq \mu_1 -\mu_2 \leq 0.5097

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

We have the following data given:

\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by \alpha=1-0.93=0.07 and \alpha/2 =0.035. And the critical value would be given by:  

z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811  

The confidence interval is given by:

(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}

And replacing we got:

(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903

(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097

And the confidence interval for the difference of means would be given by:

0.2903 \leq \mu_1 -\mu_2 \leq 0.5097

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3 years ago
Which graph represents -9x+4y≤8?
yulyashka [42]
The awnser is C!!!!!
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