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3 years ago

15

Evaluate 33b-40 when b=11.

1 answer:

tester [92]3 years ago

3 0

Answer:

323

Step-by-step explanation:

$33b-40\\\\b=11\\\\33(11)-40\\\\363-40\\\\323$

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swat32

3.2-5.7=-2.5 so its have to be a negative because a smaller number subtract a bigger number have to be equal to a negative number.

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4 years ago

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Six times a number equals 3 times the number, increased by 12. Find the number

tino4ka555 [31]

Answer:

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Step-by-step explanation:

"A number" can be rewritten as X:

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3 years ago

Which of the following is not equal to sin⁡(-230°)?

xenn [34]

From trigonometry we know that:

if $sin(\theta)=sin(\alpha)$

then, $\theta=n\pi+(-1)^n\alpha$ (where $n$ is an integer)

This can be rewritten in degrees as:

$\theta=n(180^{\circ})+(-1)^n\alpha$ .............(Equation 1)

Now, in our case, $\alpha=-230^{\circ}$

Therefore, (Equation 1) can be written as:

$\theta=n(180^{\circ})+(-1)^n(-230^{\circ})$ ..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of $\theta$ that match.

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Thus, $sin(230^{\circ})=sin(130^{\circ})$

Now, we know that: $-sin(-50^{\circ})=sin(50^{\circ})$

Let n=-1, then:

$\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}$

Thus, $sin(-230^{\circ})=-sin(-50^{\circ})$

Likewise, $sin(-230^{\circ})=sin(50^{\circ})$

Only the last option $sin(-50^{\circ})$ will never match $sin(-230^{\circ})$ because no integral value of $n$ will ever give $\theta=-50^{\circ}$

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Zigmanuir [339]

Answer:

the system of equation has infinite solution

Step-by-step explanation:

$5x_1 + x_2 = 0$ , $25x_1 + 5x_2 = 0$

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Now substitute -5x1 on second equation

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$25x_1-25x_1= 0$

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The answer is 40 is 80% of 50 ☺

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