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Sonja [21]
3 years ago
8

Which is a base unit used in the metric system?

Chemistry
1 answer:
DaniilM [7]3 years ago
4 0

Answer:

<h2> Quarts </h2><h2>Litres </h2><h2>Pints </h2><h2>Degrees Fahrenheit. </h2>

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How is thermal energy transferred during conduction? Check all that apply.
Dvinal [7]

Answer:

Thermal energy is transferred between particles that are in direct contact with each other.

Thermal energy is transferred between objects of different temperatures.

Thermal energy is transferred from fast-moving particles to slow-moving particles.

Explanation:

5 0
2 years ago
Heat flows naturally from objects that have higher energy to those with?
Vlad [161]

Answer:

heat flow

Explanation:

heat flow moves to a higher temperature to a lower temperature

8 0
2 years ago
In the sixteenth century, the geocentric theory was a daim with substantial evidence. Which of the following best describes why
Ronch [10]

Answer:

The heliocentric theory was better supported by data explaining the rotation of the planets and other bodies in the solar system.

Explanation:

3 0
2 years ago
What are three ways lakes can form?
quester [9]
Just choose 3

1) Lakes can form in hollows left by meteorite impacts (e.g. Clearwater Lakes, Quebec, Canada).

2) Lakes can form in the craters formed by volcanoes (e.g. Crater Lake, Oragon)

3) Lakes can form when a river is damed by a natural rock fall or man (e.g. Lake Mede)

4) Lakes can form where glaciers have scooped out the rock from the floor of a valley (e.g. Lake Geneva)

5) Lakes can form where block faulting lowers the land (e.g. lake Baikal)

6) lakes can form in natural depressions in the land (e.g. Lake Victoria)
4 0
2 years ago
On the basis of the information above, a buffer with a pH = 9 can best be made by using
telo118 [61]

Answer:

D H2PO4– + HPO42–

Explanation:

The acid dissociation constant for \mathbf{H_3PO_4 , H_2PO^{-}_4 ,  HPO_4^{2-}} are \mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \  5\times 10^{-13}} respectively.

\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}

\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}

\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}

The reason while option D is the best answer is that, the value of pKa for both

\mathbf{H_2PO^{-}_4 ,\  \& \  HPO_4^{2-}} lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.

Using Henderson-Hasselbach equation:

\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}

3 0
2 years ago
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