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valentinak56 [21]
3 years ago
13

Given the formula representing a compound: what is a chemical name of this compound? 2-pentene 2-pentyne 3-pentene 3-pentyne

Chemistry
1 answer:
Aleks [24]3 years ago
4 0
The question is incomplete. Complete question is attached below.
..........................................................................................................................

Correct Answer: <em>Option 1) 2-pentene</em>

Reason:
Following are the IUPAC rules for naming the compound
1) Select the longest carbon chain. In present case longest carbon chain has 5 carbon atom. Hence, it is a pentane derivative.
2) In case of alkene, replace 'e' of alkane by 'ene'
3) Give lowest number to function group. In present case, it is double bond.

Applying above rules, the IUPAC name of compound is 2-pentene

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How many electrons does the oxygen atom need to become stable?
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Answer:

2 electrons

Explanation:

Oxygen has 6 valence electrons and to be stable it needs 8. That means it needs 2 more electrons to have a full octet.

4 0
3 years ago
Read 2 more answers
In the summer of 2016, the city of Columbus Dublin Road Water Treatment plan exceeded the regulatory level of nitrate, which is
Verizon [17]

Answer:

a) 10 mg NO_3^-/L

b) 1.61*10^{-4}mol NO_3^-/L

c) 2.26 mg N/L

Carbon: C=26.64 \frac{mg C}{L}

Explanation:

<u>Nitrate</u>

First of all, is important to know that:

1 ppm=1 mg/L

a) 10 ppm of nitrate (NO_3^-) is equal to 10 mg NO_3^-/L

b) The molecular weight of nitrate is 62 g NO_3^-/mol

10 mg NO_3^-/L=0.01 g NO_3^-/L

\frac{0.01 g NO_3^-/L}{62 g NO_3^-/mol}=1.61*10^{-4} mol NO_3^-/L

c) Nitrate has 14 mg of N per 62 mg of NO3

10 mg NO_3^-/L*\frac{14 mg N}{62 mg NO_3^-}=2.26 mg N/L

<u>Carbon</u>

Carbonate has 12 mg of C per 60 mg of CO_3^{-2}

Bicarbonate has 12 mg of C per 61 mg of HCO_3^{-}

C=24 \frac{mg CO_3^{-2}}{L}*\frac{12 mg C}{60 mg CO_3^{-2}}+111 \frac{mg HCO_3^{-}}{L}*\frac{12 mg C}{61 mg HCO_3^{-}}

C=26.64 \frac{mg C}{L}

8 0
3 years ago
What process does the equation represent?
svetoff [14.1K]

The answer is d.)  fission :)

6 0
3 years ago
The temperature of a 500 ml sample of gas increases from 150 k to 300 k. what is the final volume of the sample of gas, if the p
seropon [69]
Upon a constant pressure (P), volume (V) of a gas will vary in direct proportion to changes in temperature (T). So V1/T1 = V2/T2
V2 = V1T2/T1 = (500)(300)/150
V2 = 150000/150 = 1000 mL
5 0
3 years ago
If the concentration of sugar in water is determined to be 45 g/100 ml and 135 g of sugar was used to make the solution how much
-BARSIC- [3]

Answer:

300g of water was used to make the solution

Explanation:

In the sugar solution, there are dissolved 45g of sugar in 100mL of water. The conversion factor is <em>45g Sugar = 100mL water</em>. That means when 135g of sugar are used the amount of water is:

135g sugar * (100mL water / 45g sugar) =

<h3>300g of water was used to make the solution</h3>
6 0
3 years ago
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