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enot [183]
3 years ago
14

The _______________ react with the _______________ elements to form different compounds like lithium fluoride (LiF) and sodium c

hloride (NaCl). _______________ have a full valence level and do not combine with other elements.
Chemistry
1 answer:
likoan [24]3 years ago
8 0

Answer: Alkali metals, halogens, noble gases

Explanation:

Ionic compounds are made of ions- charges. In LiF and NaCl, the first element has a +1 and the second element has a charge of -1. Elements that are +1 are alkali metals and elements that are -1 are halogens. Noble gases have full octets in their outermost valence shell, and since they're full it's so stable so it doesn't react with anything.

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If a person is sterile, he or she is:
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The graph below shows how the amount of carbon dioxide (CO2) in our atmosphere has changed since 1960. A graph that plots the am
fenix001 [56]

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greenhouse effect

Explanation:

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if a carbon atom is bonded to two hydrogen atoms and two carbon atoms which type of bond must exist between the carbon atoms​
zavuch27 [327]

Carbon to carbon bond is nonpolar covalent since the difference of their electronegativity’s is 0. Carbon has an electronegativity of 2.5. 2.5 - 2.5 is 0 making the bond between those two atoms nonpolar covalent. I hope I answered your question.

7 0
3 years ago
A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

Molarity=\frac{moles}{\text{Volume of solution(L)}}

Moles of glucose = \frac{18.5 g}{180 g/mol}=0.1028 mol

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = \frac{0.1028 mol}{0.1 L}=1.028 mol/L

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = M_1=1.208 mol

Volume of the solution taken = V_1=30.0 mL

Molarity of the solution after dilution = M_2

Volume of the solution after dilution= V_2=0.500L = 500 mL

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}

M_2=0.07248 mol/L

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}

Moles of glucose = 0.07248 mol/L\times 0.1 L=0.007248 mol

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0
3 years ago
Which of the following statements is true about gas particles?
satela [25.4K]

Answer:

There is a lot of empty space between them

Explanation:

We know that gas molecules are loosely packed,

Therefore there is a lot of intermolecular space...(Which basically means that there is a lot of space between the molecules or particles in a gas)

Happy to help.

Pls mark as Brainliest.

3 0
3 years ago
Read 2 more answers
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