Show that the equation x3 + 4x = 1 has a solution between x = 0 and x = 1

1 answer:

5 0

Intermediate Value Theorem: Suppose that f(x) is an arbitrary, continuous function on an interval [a,b] . If there exists a value L between f(a) and f(b) , then there exists a corresponding value c∈(a,b) , such that f(c)=L

f(x)=x3+4x−1

f(0)=−1f(1)=4

Since the function changes sign in the interval (0,1) , hence there exists a c∈(0,1) such that f(c)=0

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Anna is making 11 necklaces using 35 beads for each. How many beads (B) are needed to make all of the necklaces?

ss7ja [257]

Answer: c. b/35 =11

Step-by-step explanation:

the total beads is over beads of necklace and there’s 11 necklaces needed to make

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3 years ago

HELP ASAP<br> f(x)=x² what is g(x)?

murzikaleks [220]

Just by comparing the plots of f(x) and g(x), it's clear that g(x) is just some positive scalar multiple of f(x), so that for some constant k, we have

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2 years ago

Given: M(-4,-1), B(-5,-3) find the midpoint

Dmitry [639]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
M&({{ -4}}\quad ,&{{ -1}})\quad 
% (c,d)
B&({{ -5}}\quad ,&{{ -3}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -5}}-4}{2}\quad ,\quad \cfrac{-3-1}{2} \right)$