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WITCHER [35]
3 years ago
12

When Famke charges her phone, it gains 2 percentage points each minute. When Frmke uses her phone, it loses 5 percentage points

each minute. Once, Famke used her phone for some time, and then charged it for twice the amount of time she used it. In the end, her phone lost 10 percentage points. How long did Famke use her phone and how long did she charge it?
Mathematics
1 answer:
kkurt [141]3 years ago
6 0
If t is the amount of time she used it, then it lost t*(5/min) percentage points; then she charged it for 2t, so it gained (2t)*(2/min) =t*(4/min) percentage points.
This means that above this time period, the phone lost t*(5/min)-t*(4/min) =t*(1/min) percentage points; because this loss is recognized to be 10 percentage points, this means t*(1/min) =10, so t=10 min.
This means that she used her phone for 10 minutes and charged it for 20 minutes.
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Answer:

Is this for a Trig class?  just wondering

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

we want to find the Hypotenuse (Hyp)  and are given an angle and the adjacent side (adj)  sooo use  CAH  , b/c it has all of the pieces

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Cos(37) = 11 / Hyp

swap  Cos(37) and Hyp... an algebra trick you should know from college algebra or where ever you learned algebra

Hyp = 11 / Cos(37)

now solve with your handy TI 83 / 84 / 89   calculator :)  if you don't have one go get one . :D get the 89 if  you are going into engineering classes...  the 83 /84 if not. (obviously there are many many other good choices, i'm not really a calculator salesman on the side :D )

Hyp = 13.77349...

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