Answer:
The remaining liquid has a volume of 345.4 cm³.
Step-by-step explanation:
To solve this question we first need to calculate the volume of each container.
Cylindrical:
Volume = h*pi*r² = 14*3.14*(5)² = 1099 cm³
Cone:
Volume = (1/3)*h*pi*r² = (1/3)*20*3.14*(6)² = 753.6 cm³
Since the liquid from the cylinder was transfered to the cone until the latter was full, then what remains in the cylinder is it's original volume minus the cone volume. So we have:
remaining liquid = 1099 - 753.6 = 345.4 cm³
If you would like to know how many gallons remain to be used, you can do this using the following steps:
lost: 2% of 280 gallons = 2% * 280 gallons = 2/100 * 280 = 5.6 gallons
280 gallons - 5.6 gallons = 274.4 gallons
The correct result would be 274.4 gallons.
F/45 - 2/9 = 2/9....add 2/9 to both sides
f/45 = 2/9 + 2/9
f/45 = 4/9 ...multiply both sides by 45
f = 4/9 * 45
f = 180/9
f = 20 <===
The answer is 1:4 because 55 - 11 = 44 so then you have 11 red and 44 green. Take the ratio 11:44 and simplify it to 1:4, and remember order matters. So you can't do 4:1.
Answer:
i just want points lol
Step-by-step explanation:
sheesh
