999 I think... let me know if that is correct:)
The general solution of <span>y' + 2xy = (x^3) is y(x) = c1e^(-x^2)
The general solution of </span><span>ydx = (y(e^y) - 2x)dy is x = c1/(y(x))^2 + (e^y(x) ((y(x))^2 - 2y(x) + 2)/(y(x))^2
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The general solution of<span> (dP)/(dt) + 2tP = P + 4t - 2 is P(t) = c1e^(t - t^2) + 2</span>
The answer is x=0 hope this helps
