[(b+3)÷(a–2)](−4) if a=−5, b=6
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The for any number n>1 is |(3/4+2/3i)^n| greater than 1 after simplifying the complex number.
<h3>What is a complex number?</h3>It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.
We have a complex number:
Here n>1
Plug n = 2
= 145/144
= 1.0069
Which is greater than 1.
Thus, the for any number n>1 is |(3/4+2/3i)^n| greater than 1 after simplifying the complex number.
Learn more about the complex number here:
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