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lutik1710 [3]
3 years ago
8

34 less than the product of 14 and an unknown number is 78

Mathematics
2 answers:
marusya05 [52]3 years ago
8 0
The answer is 8 hope i helped you!!!!!!!!!!!!!!!!
Lubov Fominskaja [6]3 years ago
6 0
34 less than (-34) the product of (multiply) 14 (14) and an unknown (x) is (=) 78 (78)

-34+14 times x=78
14 times x=14x
14x-34=78
add 34 to both sides
14x=112
divide both sdies by 14
x=8
the number is 8
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Is 0.8 bigger than 0.706
antoniya [11.8K]
Yes because if you look at the tenths place you will see that 8 is bigger than 7
6 0
3 years ago
How many different 6- player starting squads can be formed from a volleyball team of 11 players?
aivan3 [116]
You have to calculate how many combinations of 6 people can be chosen from 11.   The formula for this is:
n! / [r! * (n-r)!]
combinations = 11! / [6! * 5!] =
11 * 10 * 9 * 8 * 7 /  5 * 4 * 3 * 2 *1 =
11 * 3 * 2 * 7 =
462 Combinations

Source:
http://www.1728.org/combinat.htm


7 0
3 years ago
Estimate how much farther sound travels through stone in 17 seconds than through a aluminum in the same time
aev [14]

Sound travels 10200m farther through stone in 17 seconds than through aluminium

Speed of sound in aluminium =  3100 m/s

The speed of sound in stone = 3700 m/s

Time taken = 17 minutes

Distance traveled = Speed  x  Time

Distance traveled by sound in aluminium in 17 seconds  = 3100    x  17

Distance traveled by sound in aluminium in 17 seconds  = 52700 m

Distance traveled by sound in stone in 17 seconds =  3700   x  17

Distance traveled by sound in stone in 17 seconds =  62900 m

Difference in the distance traveled = 62900 - 52700

Difference in the distance traveled = 10200 m

Sound travels 10200m farther through stone in 17 seconds than through aluminium

Learn more here: brainly.com/question/13096122

6 0
3 years ago
Which is the equation of a hyperbola centered at the origin with y-intercepts +12 -12, and asymptote y=3x/2
dangina [55]

Answer:

\frac{y^2}{144}-\frac{x^2}{64}=1

Step-by-step explanation:

The equation of a hyperbola centered at the origin with vertices on the y-axis is given by: \frac{y^2}{a^2}-\frac{x^2}{b^2}=1

The vertices of the hyperbola are the y-intercepts (0,12) and (0,-12)

This implies that:

2a=|12--12|

2a=24

a=12

The asymptote equation of a hyperbola is given by:

y=\pm\frac{a}{b}x

The given hyperbola has asymptote: y=\pm\frac{3}{2} x

By comparison; \frac{a}{b}=\frac{3}{2}

\implies \frac{12}{b}=\frac{12}{8}

\implies b=8

The required equation is:

\frac{y^2}{12^2}-\frac{x^2}{8^2}=1

Or

\frac{y^2}{144}-\frac{x^2}{64}=1

6 0
3 years ago
Read 2 more answers
The equation of the trend line on the scatterplot below is y= 1.3x - 0.52 Using the trend line equation, what is the predicted a
Airida [17]
Replace x in the equation with 3.5 and do the arithmetic.
  y = 1.3*3.5 -0.52
  y = 4.55 -0.52
  y = 4.03

The predicted approximate value of y is 4.03.
6 0
3 years ago
Read 2 more answers
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