<h2>
Perfect Squares</h2>
Perfect square formula/rules:
Trinomials are often organized like
.
The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.
- Perfect square trinomial:

- or

<h2>Solving the Question</h2>
We're given:
In a trinomial, we're given the
and
values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:
Therefore, the term that we can add is + 4.

To write this as the square of a bracketed expression, we can follow the rule
:

<h2>Answer</h2>


Answer:
sin 63° = a / 10
Step-by-step explanation:
With reference angle A
Sin A = BC / AB
Sin 63° = a / 10
Hope it will help :)
8 is 6.2
9 is 7
The pattern here is +0.8.
4.6 - 3.8=0.8
5.4-4.6=0.8, and so on
Answer:
Step-by-step explanation:
Given are 3 data sets with values as:
(i) 8 9 10 11 12 ... Mean =10
(ii) 7 9 10 11 13 ... Mean =10
(iii) 7 8 10 12 13 ... Mean =10
We see that data set shows mean deviations as
(i) -2 -1 0 1 2
(ii) -3 -1 0 1 3
(iii) -3 -2 0 2 3
Since variance is the square of std deviation, we find that std deviation is larger when variance is larger.
Variance is the sum of squares of (x-mean). Whenever x-mean increases variance increases and also std deviation.
Hence we find that without calculations also (i) has least std dev followed by (ii) and then (iii)
(i) (ii) (iii) is the order.
b) Between (i) and (ii) we find that 3 entries are the same and 2 entries differ thus increasing square by 9-4 twice. But between (ii) and (iii) we find that
increase in square value would be 4-1 twice. Obviously the latter is less.