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alexdok [17]
3 years ago
8

A car leaves a city with a speed of 90 mph. Three hours later and our of the same city another car in pursuit of the first leave

s with a speed of 120 mph. Find the time it takes the scond car to reach the first.
Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0
The second car is 30 minutes
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We know that, in the US, the average mile per gallon was 25 mpg in 2015. Since we don't have the mile per gallon of the car in our problem, we are going to use that average.
For our first situation, <span>drive 0.3 miles to fill up for $3.59 per gallon:
</span>\frac{25miles-----\ \textgreater \ 1gallon}{0.3miles-----\ \textgreater \ xgallons}
\frac{25}{0.3} = \frac{1}{x}
x= \frac{(1)(0.3)}{25}
x=0.012
<span>We just proved that in our trip, we used 0.012 gallon, and at $3.59 per gallon; we will pay  (0.012)(3.59)=$0.04 for that gasoline.

For our second situation, </span><span>drive 1.2 miles to fill up for $3.41 per gallon:
</span>\frac{25miles-----\ \textgreater \ 1gallon}{1.2miles-----\ \textgreater \ xgallons}
\frac{25}{1.2} = \frac{1}{x}
x= \frac{(1)(1.2)}{25}
x=0.048
We just proved that in our trip, we used 0.048 gallon, and at $3.41 per gallon; we will pay  (0.048)(3.41)=$0.16 for that gasoline.

We can conclude that is much better to drive 0.3 miles to fill up for $3.59 per gallon than drive <span>1.2 miles to fill up for $3.41 per gallon.</span>
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