What's a quadrilateral that has a 80, 100, 100, 80 degree
2 answers:
We know it's not a rectangle or square, since they are not right angles, and it has two pairs of equal angles, so it could be a rhombus/parallelogram or a trapezoid.
If the equal angles are opposite each other it is a rhombus or a parallelogram, but if the are not (which goes with how you listed the angles) it is a trapezoid.
If the equal angles are opposite each other it is a rhombus or a parallelogram, but if the are not (which goes with how you listed the angles) it is a trapezoid.
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It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.
The simplest polynomial with these characteristics would be
but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with
which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients: