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Murrr4er [49]
3 years ago
5

The after-school basketball league has 35 seventh-graders and 15 eighth-graders. What percent of the after-school basketball pla

yers are eighth-graders?

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0

30% percent of the after-school basketball players are eighth-graders.

Step-by-step explanation:

Given:

Number of Seventh graders= 35

Number of eighth graders= 15

To Find:

Percentage of  eight grade basketball players=?

Solution:

We Know that,

Percentage=\frac{(given number)}{(total number)}\times100

So according to question,  we have  

Percentage of  eight grade basketball players  

=> \frac{15}{(15+35)}\times100

=> \frac{15}{(50)}\times100

=> 0.3\times100

=> 30%

bogdanovich [222]3 years ago
4 0
The answer is 30%. This is my work below

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A large cheese pizza costs $7.50. Each additional topping for the pizza costs $1.35. If the total bill for the pizza Sally order
konstantin123 [22]

Answer: She ordered 4 toppings.

Step-by-step explanation:

Given: Total cost of pizza  = $ 12.90

Cost of pizza =$7.50

Price per topping = $1.35

Let x = Number of toppings,

Total cost of pizza = (Cost of pizza) + (price per topping) × (Number of topping)  

12.90= 7.50+1.35x\\\\\Rightarrow\ 1.35x=12.90-7.50\\\\\Rightarrow\ 1.35x=5.4\\\\\Rightarrow\ x=\dfrac{5.4}{1.35}\\\\\Rightarrow\ x=\dfrac{540}{135}=4

hence, she ordered 4 toppings.

5 0
2 years ago
A woman begins driving her car 25 km north of calgary. Some time later, the woman and her car are 100 km north of calgary.
VARVARA [1.3K]
Well the displacement of milage from the 2 places if 75km however, the women and her car are in the same place so there is no displacement. But 75km is the correct mathematical answer.
4 0
3 years ago
Directions: Match the product and quotients estimates below with the correct expression on the left
prohojiy [21]

Answer:

Answer is in attached image.

Step-by-step explanation:

Given the expressions, for which we have to find the estimates as per the expressions on the left.

The given expressions are:

1) 35 \times 23

2) 132 \div 168

3) 17.3 \times 18.4

4) 999 \div 208

5) 998 \times 211

Here, we need to find the rounded off numbers.

35 can be rounded to 40 and 23 to 20.

Therefore, equivalent to 35 \times 23 is 40 \times 20

132 can be rounded to 130 and 168 to 170.

Therefore, equivalent to 132 \div 168 is 130 \div 170.

17.3 can be rounded to 17.0 and 18.4 to 18.0.

Therefore, equivalent to 17.3 \times 18.4 is 17.0 \times 18.0.

999 can be rounded to 1000 and 208 to 210.

Therefore, equivalent to 999 \div 208 is 1000 \div 210.

998 can be rounded to 1000 and 211 to 210.

Therefore, equivalent to 998 \times 211 is 1000 \times 210.

The solution can be found in the attached image as well.

8 0
2 years ago
ASAP! Guaranteed Brainliest for first decent answer
Gelneren [198K]

Answer:

First differences means take the ordered pairs in increasing order for their x coordinates (assuming the x's go by ones), then subtract each y (except the last) from the y that comes after it.  Keep doing that and you get the first differences.  (The second differences would be what you get if you then subtract each of the first differences from the one that came after it (TMI probably but ...)

Say the points were (1,3), (2,7), (3,11) and (4,15).  The first differences are

7-3 = 4

11-7 = 4

15 - 11 = 4  all 4.  This would also be the slope.  So that is the relationship - they are the same.

6 0
3 years ago
Anyone knows how to do this please tell me how?
yulyashka [42]

Step-by-step explanation:

0.000672, 6.72×10⁵, 67.2×10‐⁴, 672×10⁴

8 0
2 years ago
Read 2 more answers
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