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3 years ago

Please help will give brainly cup

Mathematics

1 answer:

Levart [38]3 years ago

4 0

Part A: p(x) and f(x) intersect (this is the solution) at the point (-3, -2)

Part B: This would be any points of the graph of the line labeled f(x)

2 clear points would be (-3, -2) and (-7, 3)

Part C: The solution for p(x) = g(x) is the x-value for the point of intersection

x = 4 because the two graphs intersect at the point (4, 1)

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One serving of Gooey Gushers provides 12% of the daily value of vitamin C. Tim ate 312 servings of Gooey Gushers.

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a) Given expression,

12% of 312

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⇒ 10% of 312 = 31.2,

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So, 12% of 312 = 10% of 312 + 2% of 312

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b) Given,

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3 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448$

$12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152$

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

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