Answer:
23X
Step-by-step explanation:
Answer:
Step-by-step explanation
Hello!
Be X: SAT scores of students attending college.
The population mean is μ= 1150 and the standard deviation σ= 150
The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.
If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:
H₀: μ = 1150
H₁: μ ≠ 1150
α: 0.05
![Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)](https://tex.z-dn.net/?f=Z%3D%20%5Cfrac%7BX%5Bbar%5D-Mu%7D%7B%5Cfrac%7BSigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20~~N%280%3B1%29)

The p-value for this test is 0.0949
Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.
I hope it helps!
Answer:
x^8
Step-by-step explanation:
The applicable rule of exponents is ...
(x^a)(x^b) = x^(a+b)
Here you have ...
(x^3)(x^5) = x^(3+5) = x^8
The total mass, in kilograms, of the nails the carpenter bought is 3.9 kilogram
<h3><u>Solution:</u></h3>
Given that carpenter bought 750 nails
Each nail has a mass of
kilogram
To find: total mass, in kilograms of the nails bought
The total mass of the nails bought can be found out by multiplying number of nails bought by mass of each nail
Number of nails bought = 750
Mass of each nail =
kilogram
total mass of the nails bought = number of nails bought x mass of each nail


Thus the total mass of nails bought is 3.9 kilogram
Answer:
5,1
Step-by-step explanation:
x= tan27⁰ x 10 ≈ 5,1
.....