3 years ago

3x^3 - 2y^-6x^2y^2+xy for x=2/3 and y=1/2

Mathematics

1 answer:

Dominik [7]3 years ago

4 0

Answer:

-13

Step-by-step explanation:

3x^3 - 2y^-6x^2y^2+xy

x=2/3 and y=1/2

Solve :

3x^3 - 2y^-6x^2y^2+xy

Put value of x and y in this equation

= 3(2/3)^3 - 2(1/2)^-6(2/3)^2(1/2)^2+(2/3)(1/2)

= -13

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