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3 years ago

Can anyone help me? The top is geometry and the bottom is algebra...

Mathematics

1 answer:

umka21 [38]3 years ago

6 0

Answer:

<u>Geometry</u>

AC equals 13x + 7

<u>Algebra</u>

1. x = -16

2. x = 2

3. 2x^2 - 5x -7

4. (2x + 1)(x - 5)

Step-by-step explanation:

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1. Remember what we know about vertical angles and solve for x. (SHOW WORK)

marusya05 [52]

Answer:

Ans 1. $x= 7$

Ans 2.a.

$\overline {AC} \cong \overline {JL} \\\textrm{is the additional information required to prove the triangles are congruent by SAS postulate}$

Ans.2.b.

$\overline {BC} \cong \overline {KL} \\\textrm{is the additional information required to prove the triangles are congruent by the HL theorem}$

Step-by-step explanation:

Solution:

Vertically opposite angles are equal.

$\therefore (x+16) = (4x-5)\\\therefore (4x-x) = (16+5)\\\therefore (3x) = (21)\\\therefore x = 7$

2.a.

proof for Δ BAC ≅ ΔKJL by SAS postulate.

InΔ BAC and Δ KJL

BA ≅ KJ Given

∠ BAC ≅ ∠ KJL {measure each angle is 90}

$\overline{AC} \cong \overline{JL}\ \textrm{additional information require to prove the tangles are congruent by SAS postulate}\\\therefore \triangle BAC \cong \triangle KJL\ \textrm{By Side-Angle-Side postulate...PROVED}$

2.b.

proof for Δ BAC ≅ ΔKJL by HL theorem.

InΔ BAC and Δ KJL

BA ≅ KJ Given

∠ BAC ≅ ∠ KJL {measure each angle is 90}

$\overline{BC} \cong \overline{KL}\ \textrm{additional information require to prove the tangles are congruent by HL theorem}\\\therefore \triangle BAC \cong \triangle KJL\ \textrm{By Hypotenuse Leg Theorem......PROVED}$

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3 years ago

Can someone help me please?

kupik [55]

3/10=0.3=30%

725/1000=0.725=72.5%

4/10=0.4=40%

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3 years ago

1. 9 students volunteer for a committee. How many different 6-person committees can be chosen?

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2. A

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3 years ago

Please help ASAP this is timed

antiseptic1488 [7]

Answer:

1.)616 in

2.)260 ft

3.) 744 mm

Step-by-step explanation:

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3 years ago

Jonathan is using the microscope in lab. He saw a chain of bacteria that was 10 millimeters long,

AysviL [449]

We have been given that Jonathan is using the microscope in lab. He saw a chain of bacteria that was 10 millimeters long. We are asked to find the length of chain of bacteria in centimeters.

We know that 1 millimeter is equal to 0.1 centimeter.

To convert 10 milllimeters into centimeters, we will multiply 10 by 0.1.

$\text{Length of bacteria in cm}=10\text{ mm}\times \frac{0.1\text{ cm}}{\text{1 mm}}$

$\text{Length of bacteria in cm}=10\times 0.1\text{ cm}$

$\text{Length of bacteria in cm}=1\text{ cm}$

Therefore, the chain of the bacteria is 1 cm long.

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3 years ago