If 28.25 ml of 0.07439 m naoh solution was required to reach the endpoint in a khp titration and the sample weight was 1.1670 g,
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<h2>Steps:</h2>
- Remember that Density = mass/volume, or D = m/v
So firstly, we have to find the volume of the rock. To do this, we need to subtract the volume of water A from the volume of the water B. In this case:
- Water A = 30 mL
- Water B = 40 mL
- 40 mL - 30 mL = 10 mL
<u>The volume of the rock is 10 mL.</u>
Now that we have the volume, we can plug that and the density of the rock into the density equation to solve for the mass.
For this, multiply both sides by 10:
<u>Rounding to the tenths place, the mass of the rock is 36.8 g, or C.</u>