Answer:
Explanation:
A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1
Explanation:
A. Hydrogen bonding is present in CS2 but not in CO2.
B. CS2 has greater dipole moment than CO2 and thus the dipole-dipole forces in CS2 are stronger.
C. CS2 partly dissociates to form ions and CO2 does not. Therefore, ion-dipole interactions are present in CS2 but not in CO2.
D. The dispersion forces are greater in CS2 than in CO2.
<u><em>PLS MARK BRAINLIEST :D</em></u>
Answer:
7.01 mol CH4
Explanation:
STP means standard temperature and pressure, so they are basically telling you that the gas is at 1 atm and 273 K (0 degrees celsius). Now that we have the pressure, volume, and temperature we can use the ideal gas law and solve for n or moles
PV=nRT
n=PV/RT
n=(1)(157)/(0.08206)(273)
n=7.0081 (round to 3 sigfigs)
n=7.01 mol
When electrons are gained the element is negatively charged and when electrons are loss the element is positively charged